Question 29 Calculate the mass, in grams, of the water produced by dehydration synthesis of 3 moles of lysozyme. Express your answer to 4 significant figures. Example: Continuing with the previous example, we produced 40 moles of water when we made 2 moles of insulin A chain. 1. We know that the molecular mass of water is (2 x 1.008) + (1 x 15.999)- 18.02 g/mol. (Note that we cannot express the value beyond our lowest precision number, which is 1.008 for the atomic mass of hydrogen. This has 4 sig figs, so our answer cannot go beyond 4 sig figs, and must be rounded correctly. Also note that the atomic mass can have unit amu or g/mol.) 2. Therefore, the mass, in g, of the water produced is 40 mol x 18.02 g/mol = 720.6 g. Note that the unit "mol" cancels and we're left with g, which is what we want. Also, our answer here has 4 sig figs, also what we want.

Chemistry & Chemical Reactivity
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Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability
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Question 29
Calculate the mass, in grams, of the water produced by dehydration synthesis of 3
moles of lysozyme. Express your answer to 4 significant figures.
Example:
Continuing with the previous example, we produced 40 moles of water when we
made 2 moles of insulin A chain.
1. We know that the molecular mass of water is
(2 x 1.008) + (1 x 15.999) = 18.02 g/mol. (Note that we cannot express
the value beyond our lowest precision number, which is 1.008 for the atomic mass
of hydrogen. This has 4 sig figs, so our answer cannot go beyond 4 sig figs, and
must be rounded correctly. Also note that the atomic mass can have unit amu or
g/mol.)
2. Therefore, the mass, in g, of the water produced is
40 mol x 18.02 g/mol = 720.6 g.
Note that the unit "mol" cancels and we're left with g, which is what we want.
Also, our answer here has 4 sig figs, also what we want.
Transcribed Image Text:D Question 29 Calculate the mass, in grams, of the water produced by dehydration synthesis of 3 moles of lysozyme. Express your answer to 4 significant figures. Example: Continuing with the previous example, we produced 40 moles of water when we made 2 moles of insulin A chain. 1. We know that the molecular mass of water is (2 x 1.008) + (1 x 15.999) = 18.02 g/mol. (Note that we cannot express the value beyond our lowest precision number, which is 1.008 for the atomic mass of hydrogen. This has 4 sig figs, so our answer cannot go beyond 4 sig figs, and must be rounded correctly. Also note that the atomic mass can have unit amu or g/mol.) 2. Therefore, the mass, in g, of the water produced is 40 mol x 18.02 g/mol = 720.6 g. Note that the unit "mol" cancels and we're left with g, which is what we want. Also, our answer here has 4 sig figs, also what we want.
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