Solve the following problems and show your solution. 18. The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. If you were to react 52.9 g of potassium chlorate (KCIO3) with excess red phosphorus, what mass of tetraphosphorus decaoxide (P4010) would be produced? The reaction is as follows: KCIO3 + P4 --> P4010+ KCI

Solve the following problems and show your solution. 18. The reaction between potassium chlorate and red phosphorus takes place when you strike a match on a matchbox. If you were to react 52.9 g of potassium chlorate (KCIO3) with excess red phosphorus, what mass of tetraphosphorus decaoxide (P4010) would be produced? The reaction is as follows: KCIO3 + P4 --> P4010+ KCI

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter4: Stoichiometry Of Chemical Reactions

Section: Chapter Questions

Problem 69E: Outline the steps needed to solve the following problem, then do the calculations. Ether, (C2H5)2O,...

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The phosphorus in a 0.2091-g sample was precipitated as the slightly soluble (NH4)3PO4 • 12 MoO3. This precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess of Pb2+ resulted in the formation of 0.2922 g of PbMoO4. Express the results of this analysis in terms of percent P2O5.
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Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the molarity of the solution? How many mL of the 2M palmitic acid stock solution will you need? How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution in order to prepare 250 mL total volume of your desired solution?
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