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3. 5. Problem Set: Chapter 14 Correlation and Regression Based on your scatter diagram, you would expect the correlation to be The mean X Score is Mx and the mean y score is My Now, using the values for the means that you just calculated, fill out the following table by calculating the deyiations from the means for X and Y, the squares of the deviations, and the products of the deviations. 因 Scores Deviations Squared Deviations Products X Y X-Mx Y- My (X - Mx)2 (Y - My)2 (X- Mx)(Y- My) 2 4. 3. 4. 2. The sum of squares for x is SS The sum of squares for y is SS, The sum of products is SP: Because the sign of the sum of products is , the sign of the correlation coefficient The correlation coefficient is r = Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because P Type here to search DA oy 10 orrelation and RegresSion Problem Set: Chapter 14 A X 3 2. 3. 4. 9. 4. 9. 2. Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right cornN of the tool, and drag it to the appropriate location on the grid. a W PS Type here to search

3. 5. Problem Set: Chapter 14 Correlation and Regression Based on your scatter diagram, you would expect the correlation to be The mean X Score is Mx and the mean y score is My Now, using the values for the means that you just calculated, fill out the following table by calculating the deyiations from the means for X and Y, the squares of the deviations, and the products of the deviations. 因 Scores Deviations Squared Deviations Products X Y X-Mx Y- My (X - Mx)2 (Y - My)2 (X- Mx)(Y- My) 2 4. 3. 4. 2. The sum of squares for x is SS The sum of squares for y is SS, The sum of products is SP: Because the sign of the sum of products is , the sign of the correlation coefficient The correlation coefficient is r = Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because P Type here to search DA oy 10 orrelation and RegresSion Problem Set: Chapter 14 A X 3 2. 3. 4. 9. 4. 9. 2. Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right cornN of the tool, and drag it to the appropriate location on the grid. a W PS Type here to search

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 67E
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Scatter plots and calculating correlation 

3. 5. Problem Set: Chapter 14 Correlation and Regression Based on your scatter diagram, you would expect the correlation to be The mean X Score is Mx and the mean y score is My Now, using the values for the means that you just calculated, fill out the following table by calculating the deyiations from the means for X and Y, the squares of the deviations, and the products of the deviations. 因 Scores Deviations Squared Deviations Products X Y X-Mx Y- My (X - Mx)2 (Y - My)2 (X- Mx)(Y- My) 2 4. 3. 4. 2. The sum of squares for x is SS The sum of squares for y is SS, The sum of products is SP: Because the sign of the sum of products is , the sign of the correlation coefficient The correlation coefficient is r = Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because P Type here to search DA oy
Transcribed Image Text:3. 5. Problem Set: Chapter 14 Correlation and Regression Based on your scatter diagram, you would expect the correlation to be The mean X Score is Mx and the mean y score is My Now, using the values for the means that you just calculated, fill out the following table by calculating the deyiations from the means for X and Y, the squares of the deviations, and the products of the deviations. 因 Scores Deviations Squared Deviations Products X Y X-Mx Y- My (X - Mx)2 (Y - My)2 (X- Mx)(Y- My) 2 4. 3. 4. 2. The sum of squares for x is SS The sum of squares for y is SS, The sum of products is SP: Because the sign of the sum of products is , the sign of the correlation coefficient The correlation coefficient is r = Look at your scatter diagram again. If you excluded the point (10, 10), you would expect the recalculated correlation coefficient to be because P Type here to search DA oy
10 orrelation and RegresSion Problem Set: Chapter 14 A X 3 2. 3. 4. 9. 4. 9. 2. Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right cornN of the tool, and drag it to the appropriate location on the grid. a W PS Type here to search
Transcribed Image Text:10 orrelation and RegresSion Problem Set: Chapter 14 A X 3 2. 3. 4. 9. 4. 9. 2. Create a scatter diagram of these scores in the following diagram. For each of the five (X, Y) pairs, click on the plotting symbol (the black X) in the upper right cornN of the tool, and drag it to the appropriate location on the grid. a W PS Type here to search
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