Step 5: Draw the structure that best fits the mass spec data. Let's review the results of the previous steps. Step 1: The molecular ion is 27. Step 2: There are no Cl or Br atoms based on isotope pattern. Step 3: The molecular ion is odd, so there is one nitrogen. Now consider Step 4 as it relates to the unknown compound. Step 4: examine the largest peaks and calculate the difference from the molecular ion. Look for common alkyl fragments. The mass spec data shows only one base peak at m/z 27, and a smaller peak at 26, so there are no alkyl fragments. One nitrogen atom will have a molecular weight of 14, leaving 13 amu for the remaining unknown portion. A molecular weight of 13 amu can only correspond to one carbon atom and one nitrogen atom, giving the molecular formula of CHN.

Step 5: Draw the structure that best fits the mass spec data. Let's review the results of the previous steps. Step 1: The molecular ion is 27. Step 2: There are no Cl or Br atoms based on isotope pattern. Step 3: The molecular ion is odd, so there is one nitrogen. Now consider Step 4 as it relates to the unknown compound. Step 4: examine the largest peaks and calculate the difference from the molecular ion. Look for common alkyl fragments. The mass spec data shows only one base peak at m/z 27, and a smaller peak at 26, so there are no alkyl fragments. One nitrogen atom will have a molecular weight of 14, leaving 13 amu for the remaining unknown portion. A molecular weight of 13 amu can only correspond to one carbon atom and one nitrogen atom, giving the molecular formula of CHN.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL2: Mass Spectrometry

Section: Chapter Questions

Problem 26CTQ

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