Sulfur dioxide gas reacts with sodium hydroxide to form sodium sulfite and water. The unbalanced chemical equation for this reaction is given below: so-(g) + NaOH(s) - Na,SO3(s) + H,0(1) Assuming that you start with 51.9 g of sulfur dioxide and 33.4 g of sodium hydroxide and assuming that the reaction goes to completion, determine the mass of each product formed. g Na,so3 g H20 Submit

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Chapter3: Stoichiometry
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Problem 7RQ: Consider the hypothetical reaction between A2 and AB pictured below. What is the balanced equation?...
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CHEMWORK
Sulfur dioxide gas reacts with sodium hydroxide to form sodium sulfite and water. The unbalanced chemical equation for this reaction is given below:
so,(g) + NaOH(s) - Nazso3(s) + H20(1)
Assuming that you start with 51.9 g of sulfur dioxide and 33.4 g of sodium hydroxide and assuming that the reaction goes to completion, determine
the mass of each product formed.
9 NazsO3
g H20
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Transcribed Image Text:[References] CHEMWORK Sulfur dioxide gas reacts with sodium hydroxide to form sodium sulfite and water. The unbalanced chemical equation for this reaction is given below: so,(g) + NaOH(s) - Nazso3(s) + H20(1) Assuming that you start with 51.9 g of sulfur dioxide and 33.4 g of sodium hydroxide and assuming that the reaction goes to completion, determine the mass of each product formed. 9 NazsO3 g H20 Submit Submit Answer Try Another Version 3 item attempts remaining Previous Next acer Ce 23 2$ % & 7 8. 4 e y g h V b n m
Expert Solution
Step 1

The given unbalanced chemical equation is:

SO2(g) + NaOH(s)  ----> Na2SO3(s) + H2O(l)

Mass of SO2(g) initially taken = 51.9 g 

Mass of NaOH(s) initially taken = 33.4 g

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