Suppose a computer using direct mapped cache has 220 bytes of byte-addressable main memory, and a cache of 32 blocks, where each cache block contains 16 bytes.   c) To which cache block will the memory address 0x0DB63 map?

4. Assume 32 bit memory addresses, which are byte addresses. You have a direct-mapped cache with a block size of 8 bytes, and a size of 128 blocks. How many bits will the index, block offset, and tag be? How many total bits are required for the cache, including the data?

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QUESTION 2 Suppose a computer using direct mapped cache is using 216 (64K) bytes of byte-addressable main memory, and a cache size of 4096 bytes, where each cache block contains 256 bytes. a) How many blocks of main memory are there? b) What is the format of a memory address as seen by cache, i.e. what are the length of the tag, block, and offset fields? c) Given memory address 2B9D (in hexadecimal format), which block in the cache will be searched? (What is that block's id?)

P2

Please do a,b,c,d, and e  Consider a machine with a byte addressable main memory of Bytes and block size of 8 Bytes. Assume that a direct mapped cache consisting of 32 lines is used with this machine. a.How is a 16-bit memory address divided into tag, line number, and byte number? b.Into what line would Bytes with of the following address be stored? 0001- 0001- 0001- 1011 1100- 0011- 0011- 0100 1101- 0000- 0001- 1101 1010- 1010- 1010- 1010 c.Suppose the byte with address 0001 1010 0001 1010 is stored in the cache. What are the addresses of the other bytes stored along with it? d.How many total bytes of memory can be stored in the cache? e.Why is the tag also stored in the cache?