The 14 N160 molecule undergoes a transition between its rotational ground state and its rotational first excited state. Approximating the diatomic molecule as a rigid rotor, and given that the bond length of NO is 1.152 Angstroms, calculate the energy of the transition. As your final answer, calculate the temperature T in Kelvin, such that Ethermal = kBT equals the energy of the transition between NO's rotational ground state and fırst excited state.

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter20: Molecular Spectroscopy And Photochemistry
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The 14 N160 molecule undergoes a transition between its rotational ground state and its
rotational first excited state. Approximating the diatomic molecule as a rigid rotor, and given
that the bond length of NO is 1.152 Angstroms, calculate the energy of the transition. As your
final answer, calculate the temperature T in Kelvin, such that Eshermal = kBT equals the
energy of the transition between NO's rotational ground state and first excited state.
Transcribed Image Text:问题3 The 14 N160 molecule undergoes a transition between its rotational ground state and its rotational first excited state. Approximating the diatomic molecule as a rigid rotor, and given that the bond length of NO is 1.152 Angstroms, calculate the energy of the transition. As your final answer, calculate the temperature T in Kelvin, such that Eshermal = kBT equals the energy of the transition between NO's rotational ground state and first excited state.
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