The rotational constants of HFHF and DFDF are 20.956 cm−1 and 11.00 cm−1, respectively. 1K = 0.6950 cm−1 What percentage of the HFHF molecules will be in the J = 4 state at 328 KK? What percentage of the DFDF molecules will be in the J = 4 state at 328 K ?

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
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Chapter18: More Statistical Thermodynamics
Section: Chapter Questions
Problem 18.32E
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The rotational constants of HFHF and DFDF are 20.956 cm−1 and 11.00 cm−1, respectively. 1K = 0.6950 cm−1

What percentage of the HFHF molecules will be in the J = 4 state at 328 KK?

What percentage of the DFDF molecules will be in the J = 4 state at 328 K ?

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