initially have the following values: R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. R1 <-R1 + R2 R3<- R3 ^ R4, R2 <- R2 + 1 R1 <- R1 R3

initially have the following values: R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. R1 <-R1 + R2 R3<- R3 ^ R4, R2 <- R2 + 1 R1 <- R1 R3

Name: The 8-bit registers R1, R2, R3, and R4 initially have the following va
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Description: The 8-bit registers R1, R2, R3, and R4 initially have the following values:R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010Determine the 8-bit values in each register after the execution of the following sequence of microoperations

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 2PE: If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the...

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If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?
3 The 8-bit registers R1, R2, R3, and R4 initially have the following values:R1 - 1111 0010, R2- 1 1 1 1 1 1 1 1 , R3- 1011 1001 , R4 1 1 101010Determine the 8-bit values in each register after the execution of the following sequence ofmicrooperations.R1 <-R1 + R2R3<- R3 ^ R4, R2 <- R2 + 1R1 <- R1 – R3
Q2. The 8-bit registers AR, BR, CR, and DR initially have the following values: AR= 11010010, BR= 11100011, CR= 10111001 , DR= 10101011 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR <-AR + BR CR <- CR ^ DR, BR <- CR + 1 AR <-AR – CR
3) The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequenceof microoperations.AR  AR + BR Add BR + ARCR  CR AND DR, BR  BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR
The 8-bit register AR, BR, CR, and DR initially have the following values: [5]AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010Determine the 8-bit values in each register after the execution of the following sequence of microoperations.AR  AR + BR Add BR + ARCR  CR AND DR, BR  BR + 1 AND DR to CR, Increment BRAR AR - CR Subtract CR from AR
The 8-bit register AR, BR, CR, and DR initially have the following values:AR = 11010010; BR = 11111111; CR = 10101001; DR = 10101010Determine the 8-bit values in each register after the execution of the following sequence ofmicrooperations.AR <- AR + BR Add BR + ARCR <- CR AND DR, BR <- BR + 1 AND DR to CR, Increment BRAR <- AR - CR Subtract CR from AR
Consider the following two operations: (a) PC = PC + 4; (b) PC = PC + offset (offset is a positive or negative multiple of 4).Which of the following statements is true? a In the MIPS architecture, operation (b) is done by performing operation (a) as many times as required. b Operation (a) requires about 1/2 as much hardware to implement as does operation (b) c Operation (a) is simply done by replacing the right-most two bits of PC with 00. d Since (a) is a special case of (b), these two operations require the same hardware to implement.
1. Suppose 8 bit registers have following contentsX=00001111Y=10101010Z= 11011011W=00110011What will be the 8 bit values of each register after execution of following sequences ofmicrooperations ?X ← ? + ?Z←Z⋀ ?, ? ← ? + 1X←X-Z
The 8-bit register AR, BR, CR, and DR initially have the following values: AR = 11010110; BR = 11100111; CR = 10110001; DR = 10111010 Determine the 8-bit values in each register after the execution of the following sequence of microoperations. AR  AR + BR Add BR + AR CR  CR AND DR, BR  BR + 1 AND DR to CR, Increment BR AR AR - CR Subtract CR from AR
333: E8B3 8B3: 0A12 A12: 2153 Since the contents of the relevant addresses are 333 in the basic computer given above, the initial value of the PC is 333; When fetching and executing an indirectly addressing ISZ instruction, write the contents of the following registers in hexadecimal (hex) format for the T5 time. AR ........... DR......... IR ........... PC ........... SC ...........
Consider the following store instruction: SW R1, 0x000F(R0). Assume that the registers R0 and R1 are initialized with 0x00000001 and 0x53A78BC Frespectively. A section of the MIPS byte addressable data memory is shown. Give the memory word of the following memory locations after the SW operation: (a). 0x00000015. (b). 0x00000014. (c). 0x00000013. (d) 0x00000012.(e). 0x00000011. (f). 0x00000010.
Suppose a specific MCU has the following size of memories: 2 M byte of flash, starting from 0x0800_0000, 256 k byte of SRAM starting from 0x2000_0000, and 8 k byte registers for GPIOs, start at 0x4001_0000. (Note that 0x is the prefix for hexadecimal numbers.) Draw the memory map based on your calculations for the addresses.