The angle (with respect to the vertical) of a simple pendulum is given by 0 Omcos[(5.88 rad/s)t + $]. If at t = 0,0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at whic changes with the w of the SHM.) %3D

The angle (with respect to the vertical) of a simple pendulum is given by 0 Omcos[(5.88 rad/s)t + $]. If at t = 0,0 = 0.0450 rad and de/dt = -0.160 rad/s, what are (a) the phase constant o and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at whic changes with the w of the SHM.) %3D

Name: The angle (with respect to the vertical) of a simple pendulum is give
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Description: The angle (with respect to the vertical) of a simple pendulum is given by 0= 0mcos[(5.88 rad/s)t + ø]. If at t = 0, 0 = 0.0450 rad and d0/dt = -0.160 rad/s, what are (a) thephase constant o and (b) the maximum angle 0m? (Hint: Don't confuse the rate

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 13OQ

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