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The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons): Composite 1: 469.2 493.3 468.2 497 506.2 512.2 483 481.5 484 469 481.3 491.3 477.1 (Note: The average and the standard deviation of the data are respectively 485.64 Newtons and 13.898 Newtons.) Composite 2: 450.4 474.1 455.8 431.1 442.4 460.6 465.8 428.3 433.8 472.5 465.6 46 466. 468.6 450 445.6 465.9 438.5 454.9 453 (Note: The average and the standard deviation of the data are respectively 454.36 Newtons and 14.028 Newtons.) Use a 1% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Select an answer Assumption Two means T (pooled) Hypothesis Test Two means T (non-pooled) Hypothesis Test Inder Two variances F Hypothesis Test Simp Two means Z Hypothesis Test Two proportions Z Hypothesis Test Paire Two paired means T Hypothesis Test Normal populations Population standard deviations are known The number of positive and negative responses are both greater than 10 for both samples Population standard deviations are unknown but assumed equal Population standard deviation are unknown Sample rizer are both greater than 20

The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons): Composite 1: 469.2 493.3 468.2 497 506.2 512.2 483 481.5 484 469 481.3 491.3 477.1 (Note: The average and the standard deviation of the data are respectively 485.64 Newtons and 13.898 Newtons.) Composite 2: 450.4 474.1 455.8 431.1 442.4 460.6 465.8 428.3 433.8 472.5 465.6 46 466. 468.6 450 445.6 465.9 438.5 454.9 453 (Note: The average and the standard deviation of the data are respectively 454.36 Newtons and 14.028 Newtons.) Use a 1% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Select an answer Assumption Two means T (pooled) Hypothesis Test Two means T (non-pooled) Hypothesis Test Inder Two variances F Hypothesis Test Simp Two means Z Hypothesis Test Two proportions Z Hypothesis Test Paire Two paired means T Hypothesis Test Normal populations Population standard deviations are known The number of positive and negative responses are both greater than 10 for both samples Population standard deviations are unknown but assumed equal Population standard deviation are unknown Sample rizer are both greater than 20

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Population standard deviations are known Paired samples Population standard deviation are unknown The number of positive and negative responses are both greater than 10 for both samples Independent samples Population standard deviation are unknown but assumed equal Simple random samples Normal populations Sample sizes are both greater than 30 Step 1. Hypotheses Set-Up: Ho: Select an answer Ha: Select an answer? Step 2. The significance level = Step 3. Compute the value of the test statistic: Select an answer decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Provide the critical value(s) for the Rejection Region: left CV is and right CV is Step 5. Decision: CVA Is the test statistic in the rejection region? Conclusion: Select an answer where Select an answer the Select an answer units are Select an answer , and the test is Select an answer V Step 6. Interpretation: At 10% significance level we [Select an answer hypothesis in favor of the alternative hypothesis. (Round the answer to 3 and the PVA Compute the P-value of the test statistic: P-value is PVA Is the P-value less than the significance level? have sufficient evidence to reject the null 11:19 AM 7/11/2020
Transcribed Image Text:Population standard deviations are known Paired samples Population standard deviation are unknown The number of positive and negative responses are both greater than 10 for both samples Independent samples Population standard deviation are unknown but assumed equal Simple random samples Normal populations Sample sizes are both greater than 30 Step 1. Hypotheses Set-Up: Ho: Select an answer Ha: Select an answer? Step 2. The significance level = Step 3. Compute the value of the test statistic: Select an answer decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Provide the critical value(s) for the Rejection Region: left CV is and right CV is Step 5. Decision: CVA Is the test statistic in the rejection region? Conclusion: Select an answer where Select an answer the Select an answer units are Select an answer , and the test is Select an answer V Step 6. Interpretation: At 10% significance level we [Select an answer hypothesis in favor of the alternative hypothesis. (Round the answer to 3 and the PVA Compute the P-value of the test statistic: P-value is PVA Is the P-value less than the significance level? have sufficient evidence to reject the null 11:19 AM 7/11/2020
Reste The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons): Composite 1: 469.2 493.3 468.2 497 469 483 481.5 506.2 512.2 484 481.3 491.3 477.1 (Note: The average and the standard deviation of the data are respectively 485.64 Newtons and 13.898 Newtons.) Composite 2: 450.4 474.1 455.8 431.1 442.4 460.6 465.8 428.3 433.8 472.5 465.6 445.6 464.1 466.2 468.6 450 465.9 438.5 454.9 453 (Note: The average and the standard deviation of the data are respectively 454.36 Newtons and 14.028 Newtons.) Use a 1% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Select an answer Assumption Two means T (pooled) Hypothesis Test Two means T (non-pooled) Hypothesis Test Inder Two variances F Hypothesis Test Simp Two means Z Hypothesis Test Two proportions Z Hypothesis Test Paire Two paired means T Hypothesis Test Normal populations Population standard deviations are known The number of positive and negative responses are both greater than 10 for both samples Population standard deviations are unknown but assumed equal Population standard deviation are unknown Sample sizes are both greater than 30
Transcribed Image Text:Reste The breaking strength of hockey stick shafts made of two different graphite-kevlar composites yields the following results (in Newtons): Composite 1: 469.2 493.3 468.2 497 469 483 481.5 506.2 512.2 484 481.3 491.3 477.1 (Note: The average and the standard deviation of the data are respectively 485.64 Newtons and 13.898 Newtons.) Composite 2: 450.4 474.1 455.8 431.1 442.4 460.6 465.8 428.3 433.8 472.5 465.6 445.6 464.1 466.2 468.6 450 465.9 438.5 454.9 453 (Note: The average and the standard deviation of the data are respectively 454.36 Newtons and 14.028 Newtons.) Use a 1% significance level to test the claim that the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 1 is less than the standard deviation of the breaking strength of hockey stick shafts made of graphite-kevlar composite 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Select an answer Assumption Two means T (pooled) Hypothesis Test Two means T (non-pooled) Hypothesis Test Inder Two variances F Hypothesis Test Simp Two means Z Hypothesis Test Two proportions Z Hypothesis Test Paire Two paired means T Hypothesis Test Normal populations Population standard deviations are known The number of positive and negative responses are both greater than 10 for both samples Population standard deviations are unknown but assumed equal Population standard deviation are unknown Sample sizes are both greater than 30
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