The ferrate ion, FeO42, is such a powerful oxidizing agent that in acidic solution, aqueous ammonia is reduced to elemental nitrogen along with the formation of the iron(III) ion. a. What is the oxidation state of iron in FeO4 , and what is the electron configuration of iron in this polyatomic ion? Oxidation state: +6 (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s' or in condensed form as [He]2s '.) Electron configuration: [Ar]3d2 b. If 25.0 mL of a 0.303 M FeO,2 solution is allowed to react with 55.0 mL of 1.46 M aqueous ammonia, what volume of nitrogen gas can form at 25°C and 1.50 atm? Volume = mL

Modern Physics
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Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter7: Tunneling Phenomena
Section: Chapter Questions
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The ferrate ion, FeO4², is such a powerful oxidizing agent that in acidic solution, aqueous ammonia is reduced to elemental nitrogen along with the formation of
the iron(III) ion.
a. What is the oxidation state of iron in FeO4², and what is the electron configuration of iron in this polyatomic ion?
Oxidation state: +6
(Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s' or in condensed
form as [He]2s !.)
Electron configuration: [Ar]3d2
b. If 25.0 mL of a 0.303 M Fe0,2 solution is allowed to react with 55.0 mL of 1.46 M aqueous ammonia, what volume of nitrogen gas can form at 25°C and
1.50 atm?
Volume =
mL
Transcribed Image Text:[References] The ferrate ion, FeO4², is such a powerful oxidizing agent that in acidic solution, aqueous ammonia is reduced to elemental nitrogen along with the formation of the iron(III) ion. a. What is the oxidation state of iron in FeO4², and what is the electron configuration of iron in this polyatomic ion? Oxidation state: +6 (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s 2 2s' or in condensed form as [He]2s !.) Electron configuration: [Ar]3d2 b. If 25.0 mL of a 0.303 M Fe0,2 solution is allowed to react with 55.0 mL of 1.46 M aqueous ammonia, what volume of nitrogen gas can form at 25°C and 1.50 atm? Volume = mL
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