The following reaction yields 28.4 g of CH3OH: CO(g) + 2 H2(g) --> CH3OH The molar mass of CH3OH is 32.01 g/mol. Calculate the moles of H2 needed to generate this amount of product. Express your answer with three significant figures. How many liters of H2 were required to form this amount of CH3OH at 1.5 atm and 288 K? Express your answer with three significant figures. R= (L'atm)/(mol-K) 0.08206

Chemistry: Principles and Practice
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter6: The Gaseous State
Section: Chapter Questions
Problem 6.133QE
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The following reaction yields 28.4 g of CH3OH:
CO(g) + 2 H2(g)
--> CH3OH
The molar mass of CH3OH is 32.01 g/mol.
Calculate the moles of H2 needed to generate this amount of product. Express your
answer with three significant figures.
How many liters of H2 were required to form this amount of CH3OH at 1.5 atm and
288 K? Express your answer with three significant figures. R = 0.08206
(L'atm)/(mol-K)
A
Transcribed Image Text:The following reaction yields 28.4 g of CH3OH: CO(g) + 2 H2(g) --> CH3OH The molar mass of CH3OH is 32.01 g/mol. Calculate the moles of H2 needed to generate this amount of product. Express your answer with three significant figures. How many liters of H2 were required to form this amount of CH3OH at 1.5 atm and 288 K? Express your answer with three significant figures. R = 0.08206 (L'atm)/(mol-K) A
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