The function e(x) where r = R/a (see Molecules Notes on blackboard) describes the total energy of the H molecule in units of -E1 (13.6 eV). The second derivative of ɛ(x) at the equilibrium point, can be used to estimate the natural frequency of vibration of the two protons. If the ground state energy (hw/2) of this oscillator exceeds the binding energy of the system, the protons will become unbound. Estimate the oscillator frequency w and hence the vibrational energy and show that it is small compared to the binding energy of the H, molecule. You may want to consider the following quadratic expansion of the function E(x) around the minimum e(x) - Eo + k(x – xo)² xo – 0.25 < x < xo + 0.25 2 where Eo = 1.13E1, k = -0.126E1 and ro = 2.5R/a. Note Eı is a negative constant (E1=-13.6 eV)

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter20: Molecular Spectroscopy And Photochemistry
Section: Chapter Questions
Problem 14P
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6.4. Answer question throughly and with much detail as possible.
The function ɛ(x) where x =
H molecule in units of -E1 (13.6 eV). The second derivative of ɛ(x) at the equilibrium point, can be
used to estimate the natural frequency of vibration of the two protons. If the ground state energy (hw/2)
of this oscillator exceeds the binding energy of the system, the protons will become unbound. Estimate the
oscillator frequency w and hence the vibrational energy and show that it is small compared to the binding
energy of the H† molecule. You may want to consider the following quadratic expansion of the function
E(x) around the minimum
R/a (see Molecules Notes on blackboard) describes the total energy of the
e(x) ~ Eo + k(x – xo)² xo – 0.25 < x < xo + 0.25
2
where Eo = 1.13E1, k = –0.126E1 and xo = 2.5R/a. Note E1 is a negative constant (E1=-13.6 eV)
Transcribed Image Text:The function ɛ(x) where x = H molecule in units of -E1 (13.6 eV). The second derivative of ɛ(x) at the equilibrium point, can be used to estimate the natural frequency of vibration of the two protons. If the ground state energy (hw/2) of this oscillator exceeds the binding energy of the system, the protons will become unbound. Estimate the oscillator frequency w and hence the vibrational energy and show that it is small compared to the binding energy of the H† molecule. You may want to consider the following quadratic expansion of the function E(x) around the minimum R/a (see Molecules Notes on blackboard) describes the total energy of the e(x) ~ Eo + k(x – xo)² xo – 0.25 < x < xo + 0.25 2 where Eo = 1.13E1, k = –0.126E1 and xo = 2.5R/a. Note E1 is a negative constant (E1=-13.6 eV)
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