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The reaction 2 CAH10(3) + 13 O2l3)* has AG° = -5407 kJ. Determine the value of AG°, for C4H10lg). 8 CO2(g) + 10 H2O(3) Standard Free Energies of Formation of Typical Substances TABLE 18.2 at 298.15 K Substance Substance Substance AG? (kJ mol) AG? (kJ mol-') AG (kJ mol-) Ag() Aga) CaOG) -604.2 K,SO,G) -13164 -109.7 Ca(OH),) CaSO6) -896.76 N,(g) Al() NH,(g) 0.00 -1320.3 -16.7 -1576.4 -1435.2 NH,CI() - 203.9 C) (graphite) NO( NO,() N,O) N,O,() CaSO,2H,0G) -1795.7 + 86.69 -137.3 +51.84 -394.4 Fe() +103.6 CH -50.79 Fe,O,6) -741.0 +98.28 CH,A CH,OH(/) CO(NH)() -58.6 Na() Na,CO,() NAHCO,) -228.6 H,O) H,O() -166.2 -1048 -197.2 -237.2 -851.9 CO(NH,),(aq) C,H,( CH.( CH( -203.8 -95.27 NaCIG) -384.0 HNO,) H,SO() +209 -79.91 NAOH() -382 +68.12 -689.9 Na,SO,) -1266.8 HC,H,O,() Hg(/) Hg(g K) -32.9 -392.5 CH,OH(/) -174.8 PbO() -189.3 CHu() +17.3 +31.8 Ca() -300.4

The reaction 2 CAH10(3) + 13 O2l3)* has AG° = -5407 kJ. Determine the value of AG°, for C4H10lg). 8 CO2(g) + 10 H2O(3) Standard Free Energies of Formation of Typical Substances TABLE 18.2 at 298.15 K Substance Substance Substance AG? (kJ mol) AG? (kJ mol-') AG (kJ mol-) Ag() Aga) CaOG) -604.2 K,SO,G) -13164 -109.7 Ca(OH),) CaSO6) -896.76 N,(g) Al() NH,(g) 0.00 -1320.3 -16.7 -1576.4 -1435.2 NH,CI() - 203.9 C) (graphite) NO( NO,() N,O) N,O,() CaSO,2H,0G) -1795.7 + 86.69 -137.3 +51.84 -394.4 Fe() +103.6 CH -50.79 Fe,O,6) -741.0 +98.28 CH,A CH,OH(/) CO(NH)() -58.6 Na() Na,CO,() NAHCO,) -228.6 H,O) H,O() -166.2 -1048 -197.2 -237.2 -851.9 CO(NH,),(aq) C,H,( CH.( CH( -203.8 -95.27 NaCIG) -384.0 HNO,) H,SO() +209 -79.91 NAOH() -382 +68.12 -689.9 Na,SO,) -1266.8 HC,H,O,() Hg(/) Hg(g K) -32.9 -392.5 CH,OH(/) -174.8 PbO() -189.3 CHu() +17.3 +31.8 Ca() -300.4

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 1QAP: The following data are for the system A(g)2B(g) (a) How long does it take the system to reach...
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The reaction 8 CO2(3) + 10 H2O(g) 2 C,H10(9) + 13 O2ls - has AG° = -5407 kJ. Determine the value of AG°; for C4H10(g). Standard Free Energies of Formation of Typical Substances TABLE 18.2 at 298.15 K Substance Substance Substance AG? (kJ mol) AG? (kJ mol-') AG (kJ mol-) Ag() CaOG) -604.2 K,SO,G) -13164 AgC6) -109.7 Ca(OH),() -896.76 N2(g) Al() 0.00 CaSO,() -1320.3 NH,(g) -16.7 CaSO H,O6) CaSO,2H,06G) Al,O,) -1576.4 -1435.2 NH,CI() - 203.9 CG) (graphite) NO() -1795.7 + 86.69 NO,() N,0) N,0,() -137.3 +51.84 -394.4 Fe() +103.6 CH(g CH,C( CH,OH(/) Fe,O,6) H(g) H,O() -50.79 -741.0 +98.28 -58.6 Na() -166.2 -228.6 Na,CO,() -1048 CO(NH,)() -197.2 H,0() -237.2 NaHCO,() -851.9 -203.8 HCI( -95.27 NaCI6) -384.0 CH,( CH( CH( CH,OH(/) +209 HNO,(4) -79.91 NAOH() -382 +68.12 HSO() -689.9 Na,SO,() -1266.8 HC,H,0,() Hg(/) -32.9 -392.5 -174.8 PbO() -189.3 CHu) +17.3 Hg(g) +31.8 SG) Ca() K) -300.4 CaC0,() -1128.8 KCI() -408.3 SO,() -370.4 CaC,() -750.2 kJ
Transcribed Image Text:The reaction 8 CO2(3) + 10 H2O(g) 2 C,H10(9) + 13 O2ls - has AG° = -5407 kJ. Determine the value of AG°; for C4H10(g). Standard Free Energies of Formation of Typical Substances TABLE 18.2 at 298.15 K Substance Substance Substance AG? (kJ mol) AG? (kJ mol-') AG (kJ mol-) Ag() CaOG) -604.2 K,SO,G) -13164 AgC6) -109.7 Ca(OH),() -896.76 N2(g) Al() 0.00 CaSO,() -1320.3 NH,(g) -16.7 CaSO H,O6) CaSO,2H,06G) Al,O,) -1576.4 -1435.2 NH,CI() - 203.9 CG) (graphite) NO() -1795.7 + 86.69 NO,() N,0) N,0,() -137.3 +51.84 -394.4 Fe() +103.6 CH(g CH,C( CH,OH(/) Fe,O,6) H(g) H,O() -50.79 -741.0 +98.28 -58.6 Na() -166.2 -228.6 Na,CO,() -1048 CO(NH,)() -197.2 H,0() -237.2 NaHCO,() -851.9 -203.8 HCI( -95.27 NaCI6) -384.0 CH,( CH( CH( CH,OH(/) +209 HNO,(4) -79.91 NAOH() -382 +68.12 HSO() -689.9 Na,SO,() -1266.8 HC,H,0,() Hg(/) -32.9 -392.5 -174.8 PbO() -189.3 CHu) +17.3 Hg(g) +31.8 SG) Ca() K) -300.4 CaC0,() -1128.8 KCI() -408.3 SO,() -370.4 CaC,() -750.2 kJ
Choose the value of K, for the reaction at 25 °C. O K= 6.24-10947 O K, = 4.45-1023 O K, = 6.27-10-8 O Kp= 947 !!
Transcribed Image Text:Choose the value of K, for the reaction at 25 °C. O K= 6.24-10947 O K, = 4.45-1023 O K, = 6.27-10-8 O Kp= 947 !!
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