Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of e, where E = 1.0 x 10 4 J. In other words, each NO, group could have e of rotational kinetic energy, or 26, or 36, and so forth – but it cannot have just any old amount of rotational kinetic energy. -24 Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 19E. Then, some heat is bonded to a surface. added to the system, and the total rotational kinetic energy rises to 27e Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter18: Raman Spectroscopy
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Problem 18.5QAP
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Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on
the surface, but they can rotate (see sketch at right).
It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a
multiple of s, where e= 1.0 x 10* J. In other words, each NO, group could have e of rotational kinetic
energy, or 26, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy.
Two rotating NO, groups
Suppose the total rotational kinetic energy in this system is initially known to be 198. Then, some heat is
added to the system, and the total rotational kinetic energy rises to 27e. Calculate the change in entropy.
bonded to a surface.
Round your answer to 3 significant digits, and be sure it has the correct unit symbol.
Transcribed Image Text:Two nitro (NO,) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO, group can have is required to be a multiple of s, where e= 1.0 x 10* J. In other words, each NO, group could have e of rotational kinetic energy, or 26, or 3ɛ, and so forth – but it cannot have just any old amount of rotational kinetic energy. Two rotating NO, groups Suppose the total rotational kinetic energy in this system is initially known to be 198. Then, some heat is added to the system, and the total rotational kinetic energy rises to 27e. Calculate the change in entropy. bonded to a surface. Round your answer to 3 significant digits, and be sure it has the correct unit symbol.
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