Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Complete the Table based on the picture (Heat Neutralization between a strong acid and a strong base) In calculating the mass of water in the mixture, assume that the volume of the solution is mainly from water and that the volume of HCl and NaOH are negligible. Also, assume that the density of water is 1 g/mL. Volume of HCl solution = 100 mL Volume of NaOH solution = 100 mL Total Volume of mixture= 200 mL Mass of Water in the mixture=  Initial temperature of Water= 20.0°C Final Temperature of Water = 23.41°C q water = q reaction= Molarity of HCl solution= 0.500 M Molarity of NaOH solution = 0.500M moles of HCl=  moles of NaOH= Limiting Reactant= moles of limiting reactant= ΔH reaction=

Complete the Table based on the picture (Heat Neutralization between a strong acid and a strong base) In calculating the mass of water in the mixture, assume that the volume of the solution is mainly from water and that the volume of HCl and NaOH are negligible. Also, assume that the density of water is 1 g/mL. Volume of HCl solution = 100 mL Volume of NaOH solution = 100 mL Total Volume of mixture= 200 mL Mass of Water in the mixture=  Initial temperature of Water= 20.0°C Final Temperature of Water = 23.41°C q water = q reaction= Molarity of HCl solution= 0.500 M Molarity of NaOH solution = 0.500M moles of HCl=  moles of NaOH= Limiting Reactant= moles of limiting reactant= ΔH reaction=

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.86PAE: The enthalpy of vaporization for water is 40.65 kJ mol-1. As a design engineer for a project in a...
See similar textbooks
icon
Related questions
Question

Complete the Table based on the picture

(Heat Neutralization between a strong acid and a strong base)

In calculating the mass of water in the mixture, assume that the volume of the solution is mainly from water and that the volume of HCl and NaOH are negligible.

Also, assume that the density of water is 1 g/mL.

Volume of HCl solution = 100 mL

Volume of NaOH solution = 100 mL

Total Volume of mixture= 200 mL

Mass of Water in the mixture= 

Initial temperature of Water= 20.0°C

Final Temperature of Water = 23.41°C

q water =

q reaction=

Molarity of HCl solution= 0.500 M

Molarity of NaOH solution = 0.500M

moles of HCl= 

moles of NaOH=

Limiting Reactant=

moles of limiting reactant=

ΔH reaction=

Chemistry Simulations : Calorimetry Overview Learning Outcomes Experiment Experiment Step 5 Now that the experiment is complete, you can opt to show/hide the graph and/or microscopic views for subsequent runs. 23.4 1°C Click the Replay button to run the experiment again. 300mL I HCI (aq) IN2OH (ag) Click the Reset button to 200mL 600mL 500mL Time start a new experiment. 100ml The specific heat of the solution is assumed to be the 300mL 200ml same as water (4.184 J/g 100mL °C). LIQUIDS SOLIDS SOLUTIONS LIQUIDS SOLIDS SOLUTIONS HgO+ OH- Anion Cation H20 Hydrochloric acid - HCI (aq) Sodium hydroxide - NAOH (aq) RUN EXPERIMENT Vol (ml) X Show graph view 100. Vol (ml) 100. Molarity 0.500 Molarity 0.500 X Show microscopic view X Show specific heat (J/g°C) 4.184 | Show specific heat (J/g°C) 4.184 Replay Reset Temp erature
Transcribed Image Text:Chemistry Simulations : Calorimetry Overview Learning Outcomes Experiment Experiment Step 5 Now that the experiment is complete, you can opt to show/hide the graph and/or microscopic views for subsequent runs. 23.4 1°C Click the Replay button to run the experiment again. 300mL I HCI (aq) IN2OH (ag) Click the Reset button to 200mL 600mL 500mL Time start a new experiment. 100ml The specific heat of the solution is assumed to be the 300mL 200ml same as water (4.184 J/g 100mL °C). LIQUIDS SOLIDS SOLUTIONS LIQUIDS SOLIDS SOLUTIONS HgO+ OH- Anion Cation H20 Hydrochloric acid - HCI (aq) Sodium hydroxide - NAOH (aq) RUN EXPERIMENT Vol (ml) X Show graph view 100. Vol (ml) 100. Molarity 0.500 Molarity 0.500 X Show microscopic view X Show specific heat (J/g°C) 4.184 | Show specific heat (J/g°C) 4.184 Replay Reset Temp erature
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

These weren't answered here... What are the answer of these?

Limiting Reactant=

moles of limiting reactant=

Solution
Bartleby Expert
SEE SOLUTION
Knowledge Booster
Solutions
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry for Engineering Students
Chemistry for Engineering Students
Chemistry
ISBN:
9781337398909
Author:
Lawrence S. Brown, Tom Holme
Publisher:
Cengage Learning
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Physical Chemistry
Physical Chemistry
Chemistry
ISBN:
9781133958437
Author:
Ball, David W. (david Warren), BAER, Tomas
Publisher:
Wadsworth Cengage Learning,
SEE MORE TEXTBOOKS