To 2.12L of 0.473M NaOH, you add 3.52L of a second NaOH solution of an unknown concentration. The resulting solution is titrated and determined to be 1.170M. Assuming the volumes are additive, calculate the molarity of the second NaOH solution.

To 2.12L of 0.473M NaOH, you add 3.52L of a second NaOH solution of an unknown concentration. The resulting solution is titrated and determined to be 1.170M. Assuming the volumes are additive, calculate the molarity of the second NaOH solution.

Introductory Chemistry For Today

8th Edition

ISBN:9781285644561

Author:Seager

Publisher:Seager

Chapter9: Acids, Bases, And Salts

Section: Chapter Questions

Problem 9.98E

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

To 2.12L of 0.473M NaOH, you add 3.52L of a second NaOH solution of an unknown concentration.
The resulting solution is titrated and determined to be 1.170M. Assuming the volumes are additive,
calculate the molarity of the second NaOH solution.

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