To compare customer satisfaction levels of two competing cable television companies, 174customers of Company 1 and 355 customers of Company 2 were randomly selected and wereasked to rate their cable companies on a five-point scale, with 1 being least satisfied and 5 beingmost satisfied.Thesurveyresults are summarized in the following table.Company 1Company 2= 174n2 = 355I1 = 3.51T2 = 3.24S1 = 0.51S2 = 0.52It is desired to test, at a 0.01 level of significance, whether the data provide sufficient evidence toconclude that Company 1 has a higher mean satisfaction rating than does Company 2.Let u1 and u2 denote the population mean satisfaction ratings for Company 1 and Company 2,respectively.We consider the hypotheses: Ho : µ1 - H2 = 0 versus H1: 1- P2 > 0.%3DThe value of the test statistic is(Write your answer precise to two decimalplaces, e.g., 1.78, 2.56, -3.71, 0.35.)The data(write "do" or "do not") provide sufficient evidence, at the 0.01 levelof significance, that the mean customer satisfaction for Company 1 is higher than that forCompany 2.

We have given that Sample size n1=174 , n2= 355 Sample mean xbar1 = 3.51 , xbar2 = 3.24 Standard…

Answered: To compare customer satisfaction levels…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A large manufacturing company investigated the service it received from its suppliers and discovered that, in the past, 38% of all material shipments were received late. However, the company recently installed a just-in-time system in which suppliers are linked more closely to the manufacturing process. A random sample of 150 deliveries since the just-in-time system was installed reveals that 33 deliveries were late. If we want to test whether the proportion of late deliveries was reduced signicantly at = 0:10 the null and alternative hypotheses are a. Null hypothesis (H0) b. Alternative hypothesis (HA)
The director of an obesity clinic in a large northwestern city believes that drinking soft drinks contribute to obesity in children. To determine whether a relationship exists between these two variables, she conducts the following pilot study. Eight- 12-year-old male volunteers are randomly selected from children attending a local junior high school. Parents of the children are asked to monitor the number of soft drinks consumed by their child over a one week period. The children are weighed at the end of the week and their weights converted into body mass index (BMI) values. The BMI is a common index used to measure obesity and takes into account both height and weight. An individual is considered obese if they have a BMI value 30. The following data or collected: child. # of soft drinks consumed BMI 1 3 20 2 1 18 3…
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An experiment to determine if a migraine medication decreases a person's average number of monthly migraines is performed on 400 people who report they have several migraines a month. Researchers randomly assigned 200 people to the treatment group and 200 people to the control group. After the study, the researchers determined that 48 of the subjects in the treatment group and 28 of the subjects in the control group average fewer migraines per month. The data from the two groups are resampled 150 times, and the table shows the distribution of the differences of the proportions for the reconfigured treatment and control groups.
The authors of the article "Adjuvant Radiotherapy and Chemotherapy in Node-Positive Premenopausal Women with Breast Cancer"† reported on the results of an experiment designed to compare treating cancer patients with chemotherapy only to treatment with a combination of chemotherapy and radiation. Of the 154 individuals who received the chemotherapy-only treatment, 76 survived at least 15 years, whereas 98 of the 164 patients who received the hybrid treatment survived at least that long. With p1 denoting the proportion of all such women who, when treated with just chemotherapy, survive at least 15 years and p2 denoting the analogous proportion for the hybrid treatment, p̂1 = (rounded to three decimal places) and p̂2 = (rounded to three decimal places). A confidence interval for the difference between proportions based on the traditional formula with a confidence level of approximately 99% is 0.494 − 0.598 ± (2.58) (0.494)(0.506) 154 + (0.598)(0.402) 164…
A researcher is comparing the occurrence of nausea as a side-effect in two brands of medication: Brand A and Brand B. For a random sample of 150 Brand A users, 66 experienced nausea as a side-effect. For a random sample of 200 Brand B users, 118 experienced nausea as a side-effect. Can the researcher conclude that the proportion of all Brand A users who experience nausea as a side-effect is different from the proportion of all Brand B users who experience nausea as a side-effect. For the hypothesis testing scenario above, the researcher concludes that the two proportions are different at the 0.01 significance level. Compute the 99% confidence interval to estimate the difference.
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A consumer advocacy group wanted to study whether different airline carriers differed in terms of their delayed flights. In particular, the researchers were interested in the relationship between p1, the proportion of Alpha Airlines flights that were delayed at least 15 minutes, and p2, the proportion of Beta Airlines flights that were delayed at least 15 minutes. A random sample of 1,000 Alpha flights and a separate random sample of 1,000 Beta flights found that 67 of the Alpha fights and 160 of the Beta flights were delayed at least 15 minutes. The conditions for inference were checked and verified. Does this set of samples provide strong evidence that Alpha Airlines has a smaller proportion of flights that are delayed at least 15 minutes than Beta Airlines, at the α = 0.05 significance level? Find the z-table here. A. The test statistic is z = –6.56 and the P-value ≈ 0. Since the P-value ≈ 0 < 0.05, there is not sufficient evidence that Alpha Airlines has fewer delayed…
31% of all pygmy softshell tortoises have stripes on their shells. A herpetologist in Cititon collects a sample of 28 pygmy softshell tortoises and finds that 8 of them have stripes on their shells. Is there enough evidence to conclude, at a significance of alpha = 0.05, that the proportion of pygmy softshell tortoises in Cititon with stripes on their shells is less than 31%? What is the claim? What is the null hypothesis? What is the alternative hypothesis? What is the test statistic? What is/are the critical value(s)? Do we reject the null hypothesis? What conclusion do we draw? What is the P-value for the problem above?

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