Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1) find the volume at equivalence point of both trial 2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
Trial 1: Initial pH= 3.92mL Mass of KHP and Paper= 0.868g Mass of paper= 0.357g Mass of KHP= 0.511g Trial 2: Initial pH= 4.09ml Mass of KHP and Paper= 0.870g Mass of paper= 0.359g Mass of KHP= 0.511g 1) find the volume at equivalence point of both trial 2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter18: Acids And Bases
Section18.3: Hydrogen Ions And Ph
Problem 40SSC
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Trial 1:
Initial pH= 3.92mL
Mass of KHP and Paper= 0.868g
Mass of paper= 0.357g
Mass of KHP= 0.511g
Trial 2:
Initial pH= 4.09ml
Mass of KHP and Paper= 0.870g
Mass of paper= 0.359g
Mass of KHP= 0.511g
1) find the volume at equivalence point of both trial
2) find the pH at equivalence point of both trial and calculate the molarity of the NaOH solution from each result and calculate the mean.
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