Trial KIO3 H2O Starch Time (sec) Rate 100/t (show calculations Test Tube 1 Test Tube 2 with units) 10 ml 0 ml 10 ml 18 7 ml 3 ml 10 ml 27 3 5 ml 5 ml 10 ml 32 2 ml 8 ml 10 ml 68
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- 1. Find HCl Mol weight 2. Find NH3 Mol. weight 3. HCI Diff. Distance: 10 4. NH3Diff. Distance: 60 5. Find rate ration (exp.) : Rate ration =Distance A/Distance B 6. Find rate ration (theor.) = MWb/MWaPLS HELP VERY URGENT Q5Trial Conc. A (M) Conc. B (M) Rate 1 0.706 0.771 6829.54 2 0.706 3.855 34147.702 3 2.118 0.771 6829.54 4 0.647 0.407 ? Given the information in the table above provide the rate for Trial 4Write all answers in standard form rounded to 3 decimal places " Order for A Order for B Overall Order The rate for Trial 4 Round to nearest whole number
- Initial temp: 19.06 C trial 1: 0.5 M concentration trial 2 : 1.0 M concentration 200 mL of HCl and 200 mL of NaOH are combined in an insulated container. HCl = 0.5 mol/ml x 200 x 10^-3 ml = 0.1 mol NaOH = 0.5 mol/ml x 200 x 10^-3 ml= 0.1 mol H+(aq) + OH-(aq) - - -> H2O (l) ∆H H++ = 0, ∆H OH−− = -230 kJ/mol, ∆H H2O = -286 kJ/mol ∆H reactants = ∆H H++ + ∆H OH−− = -230 + 0 = -230 kJ/mol ∆H reactants = -286 kJ/mol - ( -230 kJ/mol) = -56 kJ/mol For each trial, calculate how much energy is released during this reaction.urgent pls I will rate right away no need of explanationy= mx+ b Slope () = -4E-09 y-intercept () = 0.4021 and OD= 0.540 , Calculate the concentration (x)
- Which of the following would result in an increase in the calculated ngas 10, assuming the rest of the parameters are held constant? I. Inserting 23.0 mg instead of the prescribed 15.0mg of folded Mg ribbon into the eudiometer. II. Performing the experiment in a different laboratory with a cooler temperature. III. A shorter equilibration time prior to volume measurement. IV. Acid used was 12.0 M HNO3 instead of 6.0 M HCI.You are trying to come up with a drug to inhibit the activity of an enzyme thought to have a role in liver disease. In the laboratory the enzyme was shown to have a Km of 1.0 x 10-6 M and Vmax of 0.1 micromoles/min.mg measured at room temperature. You developed an uncompetitive inhibitor. In the presence of 5.0 x 10-5 M inhibitor, the apparent Vmax was determined to be 0.02 micromoles/min.mg. What is the Ki of the inhibitor?Full accurate details Mechanisms need steps by steps. Dont answer recent u people answer not good. Need new computational method etc mechanism steps by steps
- Faat pls i will give u like for sure solve this question correctly in 5 min plsExtraction of Caffeine Post-lab 5. On the report sheet, you calculated your percent recovery of caffeine. a. If your percent was less than 90%, give at least one reason why it was less. b. A group of students have their percent yield more than 100%, give at least one reasonwhy it was more than 100%. Do NOT simply say “human error.” Be specific about the typesof errors (human or otherwise) that may have occurred, leading to a recovery more than eorequal to 100% (Is this possible Why?) 6. Based on what you observed during this experiment, is dichloromethane denser OR lessdense than water? Explain your reasoning. 7. Based on what happened in this experiment, is caffeine more soluble in water OR moresoluble in dichloromethane? Explain your reasoning.HELP !!!!!!!!! PLEASE HELP ME ON THE DARK BULLET POINT TABLE CALCULATION. BE SURE UPLOAD THE GRAPH. make sure Answer all of them Experiment 1 Exact concentration of H2O2 stock solution (M) 1.014 Temperature of water bath (°C) 24 Experiment 1: Volume of O2 vs time for decomposition of H2O2 Time (min) Volume of O2 (mL)2.0 0.00 4 1.22 6 2.41 8 3.64 10 4.93 12 6.34 14 7.78 16 9.49 18 10.99 20 12.35 22 14.64 24 16.31 26 19.16 28 20.97 30 24.52 32 26.03 34 28.99 36 32.30 38 35.17 40 38.83 42 44.83 44 50.50 46 58.26 48 63.46 Experiment 2: Volume of O2 vs time for decomposition of H2O2 Time (min) Volume of O2 (mL)2.0 0.00 4 0.63 6 1.31 8 1.96 10 2.42 12 2.93 14 3.56 . Experiment 3: Volume of O2 vs time for decomposition of H2O2 Time (min) Volume of O2 (mL)2.0 0.00 4 0.45 6 0.88 8 1.44 10 2.29 12 2.92 14 3.51 Calculations For all three experiments plot the volume of O2 evolved in…
