U ELECTRUNIC STRUCTURE Interpreting the angular probability distribution of an orbital This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. B point A point B compare PA to P P,< P, 100 pm in front of the nucleus, along the -y axis. 100 pm to the left of the nucleus, along the -x axis. O P, = P. O P P O P P. Explanation Check O 2021 McGraw-HIII Education. All Rights Reserved. Terms of UseI Privacy Accessibility

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter5: Quantum Mechanics And Atomic Structure
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Problem 5P: Estimate the probability of finding an electron which is excited into the 2s orbital of the H atom,...
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O ELECTRONIC STRUCTURE
Interpreting the angular probability distribution of an orbital
This sketch is about 800 pm wide.
The coordinate (x, y, and z) axes are also shown.
You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.
i II IIIII
Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of
finding the electron at point A, compares to PR, the probability of finding the electron at point B.
point A
point B
compare PA to P
P
100 pm in front of the nucleus, along the -y axis.
100 pm to the left of the nucleus, along the -x axis.
O P.
= P.
O P, > P
100 pm behind the nucleus, along the +y axis.
100 pm below the nucleus along the -z axis.
O P, = P
O P,> P
O P, <P.
100 pm to the right of the nucleus, along the +x axis.
100 pm above the nucleus, along the +z axis.
O P, = P,
O P, > P,
Explanation
Check
O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility
MacBook Pro
Transcribed Image Text:O ELECTRONIC STRUCTURE Interpreting the angular probability distribution of an orbital This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. i II IIIII Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. point A point B compare PA to P P 100 pm in front of the nucleus, along the -y axis. 100 pm to the left of the nucleus, along the -x axis. O P. = P. O P, > P 100 pm behind the nucleus, along the +y axis. 100 pm below the nucleus along the -z axis. O P, = P O P,> P O P, <P. 100 pm to the right of the nucleus, along the +x axis. 100 pm above the nucleus, along the +z axis. O P, = P, O P, > P, Explanation Check O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility MacBook Pro
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