Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Appl Of Ms Excel In Analytical Chemistry
2nd Edition
ISBN:9781285686691
Author:Crouch
Publisher:Crouch
Chapter2: Basic Statistical Analysis With Excel
Section: Chapter Questions
Problem 12P
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Use your average AA concentration to calculate the mass percent of acetic acid in vinegar.

Results
Quantity
Trial 1
Trial 2
Trial 3
M NaOH
0.992 M
0.992 M
0.992 M
V initial buret
0 ml
15 ml
30 ml
V Final buret
13.1 ml
28.2 ml
47.9 ml
Vep = VNAOH added
= Vf - Vi
(47.9ml-30ml)=
(13.1ml-0ml)=
13.1 ml
(28.2ml-15ml)=
13.2ml
17.9ml
Vep = VNAOH in L
0.0131 L
0.0132 L
0.0179 L
moles NaOH=
(0.992M)(0.0131 L)= | (0.992M)(0.0132 L)= | (0.992M)(0.0179 L)=
MNAOH x VNaOH
0.0129 mol
0.0130 mol
0.178 mol
moles AA = moles
0.0129 mol
0.0130 mol
0.178 mol
NaOH
Vsample = Vacid
0.0150 L
0.0150 L
0.0150 L
Actual molarity of
0.0129mol/0.0150L=
0.0130mol/0.0150L=
0.0178mol/0.0150L=
AA
0.86 M
0.87 M
1.186 M
Average Molarity of AA: (0.86M)(0.87M)(1.186M)=0.887 M
Transcribed Image Text:Results Quantity Trial 1 Trial 2 Trial 3 M NaOH 0.992 M 0.992 M 0.992 M V initial buret 0 ml 15 ml 30 ml V Final buret 13.1 ml 28.2 ml 47.9 ml Vep = VNAOH added = Vf - Vi (47.9ml-30ml)= (13.1ml-0ml)= 13.1 ml (28.2ml-15ml)= 13.2ml 17.9ml Vep = VNAOH in L 0.0131 L 0.0132 L 0.0179 L moles NaOH= (0.992M)(0.0131 L)= | (0.992M)(0.0132 L)= | (0.992M)(0.0179 L)= MNAOH x VNaOH 0.0129 mol 0.0130 mol 0.178 mol moles AA = moles 0.0129 mol 0.0130 mol 0.178 mol NaOH Vsample = Vacid 0.0150 L 0.0150 L 0.0150 L Actual molarity of 0.0129mol/0.0150L= 0.0130mol/0.0150L= 0.0178mol/0.0150L= AA 0.86 M 0.87 M 1.186 M Average Molarity of AA: (0.86M)(0.87M)(1.186M)=0.887 M
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