Using the punnet square (di-hybrid cross) solve the following: In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can inhibit pigment formation. The epistatic recessive allele, i, on the other hand, permits pigment deposition in the fur. -Cross the following parents: bbIi x BBIi 4th Question: How many of the offspring could be albino (white)?

Using the punnet square (di-hybrid cross) solve the following: In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can inhibit pigment formation. The epistatic recessive allele, i, on the other hand, permits pigment deposition in the fur. -Cross the following parents: bbIi x BBIi 4th Question: How many of the offspring could be albino (white)?

Name: Using the punnet square (di-hybrid cross) solve the following:In a cer
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Description: Using the punnet square (di-hybrid cross) solve the following:In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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Using the punnet square (di-hybrid cross) solve the following: In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can inhibit pigment formation. The epistatic recessive allele, i, on the other hand, permits pigment deposition in the fur. -Cross the following parents: bbIi x BBIi 1st Question to answer ---- How many different possible genotypes are there among the offspring? 2nd Question to answer ---- How many of the offspring could be black? 3rd Question to answer ---- How many of the offspring could be brown? 4th Question to answer ---- How many of the offspring could be albino (white)? Different Possible Genotypes Black Offspring Brown Offspring Albino/White Offspring
Using the punnet square (mono-hybrid cross) solve the following: In some cattle the genes for brown hair (B) and for white hair (W) are co-dominant, this condition allows cattle to show brown & white hair at the same time, and this resulting appearance is often referred to as Roan (BW). -A roan cow is crossed with a roan bull 1st Question to answer ---- How many different possible genotypes are there among the offspring? 2nd Question to answer ---- How many of the offspring could be brown? 3rd Question to answer ---- How many of the offspring could be white? 4th Question to answer ---- How many of the offspring could be roan?
A homozygous strain of corn that produces yellow kernels is crossed with another homozygous strain that produces purple kernels. When the F1 are interbred, 197 of the F2 are yellow and 153 are prurple. Give the genotypes of the yellow and purple F2 and propose a genetic model that explains the inheritance of these kernel colors in corn.
In poultry, the genotype–phenotype relationships forcomb shape are R/– P/–, walnut; R/– p/p, rose, r/r P/–, pea;and r/r p/p, single. What will be the comb characters ofthe offspring of the following crosses? a. A walnut crossed with a single b. A rose crossed with a walnut c. A rose crossed with a pea d. A walnut crossed with a walnut Note- a, b, c, are already solved, posting this one to get the answers of d sub topic.
In cats, the gene for calico (multicolored) cats is both sex-linked and codominant. Due to a phenomenon known as dosage compensation, females that receive a B and an R gene have black and orange splotches on white Males can only be black or orange, but never calico. a. What would a calico cat’s genotype be? b. Show the cross of a female calico cat with a black male. What percentage of the kittens will be black and male? c. What percentage of the kittens will be calico and male? d. What percentage of the kittens will be calico and female? e. Show the cross of a female black cat with a male orange cat. f. What percentage of the kittens will be calico and female? What color will all the male cats be?
DIHYBRID CROSS: In rabbits, assume that spotted skin (G) is dominant over non-spotted skin (g) and that wooly hair (B) is dominant over nonwooly hair (b). Cross a marriage between a male rabbit with the genotype GGBB with a female rabbit with the genotype ggbb. Show the P1, F1, P2 and F2 generation on a Punnett Square. Give the genotypic and phenotypic ratio of the offspring and the tally of genotype and phenotype of the offspring.
A cross in Drosophila melanogaster involved the recessive X-linked genes for white eye (w), yellow body (y), and cut wings (c). A wild-type tri-hybrid female was crossed with wild-type males and only the male offspring were tallied. On the basis of the results shown below, which of the choices shown best represents the genetic map of the three loci on the X-chromosome? Phenotype Male Offspring + y ct 494 w + + 394 + + ct 28 w y + 35 + y + 105 w + ct 101 w y ct 5 + + + 3
In classical Mendelian genetics, how can one check the genotype of a parent (A) expressing the characters of a dominant allele? Select one: a. By performing a back cross with a recessive homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character. If the parent A was, instead, a heterozygote, then 50% of the F1 progeny will express the recessive character (homozygote recessive) and 50% the dominant one (heterozygotes). b. It is impossible to check such genotype without using specific molecular assays. c. By performing a back cross with a dominant homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character.
In poultry, two independently assorting genes together determine the structure of the comb. Thus, when R is the only dominant allele present, the fowl possesses a rose comb; when P is only dominant allele present, a ‘pea’ comb is produced; when both dominants are present, a ‘walnut’ comb is produced; when only the recessive alleles are present, a ‘single’ comb is obtained. (a) What are the possible genotypes of all the phenotypes obtainable? Determine the genotype of the parent birds in the following crosses: (b) Rose x walnut produced 3/8 walnut, 3/8 rose, 1/8 rose, 1/8 pea and 1/8 single offspring. (c) Walnut x single produced ¼ walnut and ¼ pea, ¼ rose and ¼ single offspring (d) Rose x pea produced 6 walnut and 5 rose offspring.
REad and analyzed the following genetic problem. Show complete solution (Genotypes of P, Punnet Square and GR,PR). 1. In the garden peas, green pod color is dominant over yellow pods. Also, round seed shape is dominant over wrinkled seed. Cross fertilization was done between a pea that is homozygous dominant for pod color with heterozygous round shape and another pea that is heterozygous for both pod color and seed shape. Determine the genotypic and phenotypic ratio of teh offspring.
In rabbits, the color of body fat is controlled by a single genewith two alleles, designated Y and y. The outcome of this traitis affected by the diet of the rabbit. When raised on a standardvegetarian diet, the dominant Y allele confers white body fat,and the y allele confers yellow body fat. However, when raisedon a xanthophyll-free diet, a homozygote yy rabbit has whitebody fat. If a heterozygous rabbit is crossed to a rabbit withyellow body fat, what are the proportions of offspring withwhite and yellow body fat when raised on a standard vegetariandiet? How do the proportions change if the offspring are raisedon a xanthophyll-free diet?
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous for both of these recessive traits. The following data was produced from the cross. Test these data to determine if they are significantly different from the expected phenotypic ratio. Remember to use the 5% level of significance Wild eye Wild body – 102, Wild eye Ebony body – 94, Sepia eye Wild body – 100, Sepia eye Ebony body – 93. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject.