What does the following function do for a given Linked List?  void fun1(struct node* head) { if(head == NULL) return; fun1(head->next); printf("%d ", head->data); }

In c++, how do I display the last node in a linked list?

struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };

JAVA CODE Learning Objectives: Detailed understanding of the linked list and its implementation. Practice with inorder sorting. Practice with use of Java exceptions. Practice use of generics.   You have been provided with java code for SomeList<T> class.  This code is for a general linked list implementation where the elements are not ordered.  For this assignment you will modify the code provided to create a SortedList<T> class that will maintain elements in a linked list in ascending order and allow the removal of objects from both the front and back.  You will be required to add methods for inserting an object in order (InsertInorder) and removing an object from the front or back.  You will write a test program, ListTest, that inserts 25 random integers, between 0 and 100, into the linked list resulting in an in-order list.  Your code to remove an object must include the exception NoSuchElementException.  Demonstrate your code by displaying the ordered linked list and…

Java language Write a method to insert an array of elements at index in a single linked list and then display this list. The method receives this array by parameters

T/F: All Linked Lists must have head node.

#include <iostream> using namespace std; #define SIZE 5   //creating the queue using array int A[SIZE]; int front = -1; int rear = -1;   //function to check if the queue is empty bool isempty() { if(front == -1 && rear == -1) return true; else return false; }   //function to enter elements in queue void enqueue ( int value ) { //if queue is full if ((rear + 1)%SIZE == front)    cout<<"Queue is full \n"; else {  //now the first element is inserted  if( front == -1)     front = 0; //inserting element at rear end rear = (rear+1)%SIZE;   A[rear] = value; } }   //function to remove elements from queue void dequeue ( ) { if( isempty() )  cout<<"Queue is empty\n"; else //only one element if( front == rear )  front = rear = -1; else  front = ( front + 1)%SIZE; }   //function to show the element at front void showfront() { if( isempty()) cout<<"Queue is empty\n"; else cout<<"element at front is:"<<A[front]; }   //function to display the queue void…

struct node{int num;node *next, *before;};start 18 27 36 45 54 63 The above-linked list is made of nodes of the type struct ex. Your task is now to Write a complete function code to a. Find the sum of all the values of the node in the linked list. b. Print the values in the linked list in reverse order. Use a temporary pointer temp for a and b. i dont need a full code just the list part

Having trouble with creating the InsertAtEnd function in the ItemNode.h file below.  "    // TODO: Define InsertAtEnd() function that inserts a node    //       to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts  ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() {    ItemNode *headNode;  // Create intNode objects                                                       ItemNode *currNode;    ItemNode *lastNode;     string item;    int i;    int input;     // Front of nodes list                                                                             headNode = new ItemNode();    lastNode = headNode;     cin >> input;     for (i = 0; i < input; i++) {        cin >> item;…

With Head node or not? statement is: if(p->rlink != first) p = p->rlink; O a. It is a Doubly linked list without Head node. O b. It is a Doubly linked list with Head node.