What is the worst case efficiency for a path compression algorithm?
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What is the worst case efficiency for a path compression
a) O(N)
b) O(log N)
c) O(N log N)
d) O(M log N)
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- Can I at least ensure that the length of a bitstream won't rise due to my compression algorithm?1. Compact discs record two channels (left and right) of music at a sampling frequency of ??=44.1kHz for each channel. If each sample is encoded with 16 bits, and one byte is 8 bits, how many bytes are required to store 48.1 seconds of music? 2. Consider a system that uses 8-bit ASCII codes to encode letters. How long (in microseconds) will it take to transmit the bit sequence encoding Hello-World! if we use a bit time of 4 samples per bit, and transmit samples at a rate of 1MHz? 3. The ASCII table below gives the ASCII codes for common alphanumeric characters and symbols listed from MSB to LSB. What is the bit sequence encoding the message 113? Assume that we transmit the codes of each character in sequence with the LSB first.Consider a SEC code that protects 8-bit words with 4 parity bits. If we read the value0xABC, is there an error? If so, correct the error.Note: 0xABC = 1010 1011 1100Hint: Decode the 12-bit encoded data and find if there is an error.
- Suppose we are working with an error-correcting code that will allow all single-bit errors to be corrected for memory words of length 7. We have already calculated that we need 4 check bits, and the length of all code words will be 11. Code words are created according to the Hamming algorithm presented in the text. We now receive the following code word: 1 0 1 0 1 0 1 0 1 1 0 Assuming odd parity, is this a legal code word? If not, according to our error-correcting code, where is the error?Compare and contrast the performance implications of various memory compression algorithms in different computing scenarios.What is the largest n for which one can solve within 3 minutes a problem using an algorithm that requires f(n) bit operations, where each bit operation is carried out in 10-12seconds, with these functions of n?
- q1- Public key algorithms are based on mathematical functions rather than on simple operations on bit patterns. Select one: True FalseAs information centers are progressively centered on energy efficiency, it gets to be imperative to create Low control usage of the different applications that run on them. Data or Information compression plays a basic part in information centers to reduce storage capacity and communication costs. This work pivot on building a Low control, High performance execution usage for canonical Huffman encoding. Suppose given Letters I, Q, R, A, C, M, P, U, S with following frequencies. Frequency Table Character Frequency I 20 Q 11 R 8 A 12 C 49 M 10 P 5…You are given sixty-four bit integer and a list of bit position p[1] p[2], p[k] for k < 65 generate new sixty-four bit integer that lowest bits are the extracted bits from integer X at input bit positions p. Explain your steps clearly. CONSTANT TIME AND SIMD instrict. DONT ANSWER BY USING LOOPS!
- The latest super-duper supercomputer has memory locations that are 64-bits wide. What is the largest unsigned integer that can be stored in one memory location? Suppose that we use sign-magnitude for storing negative numbers and dedicate one bit for a sign bit. What would be the largest POSITIVE integer that can be stored in a memory location.Show Steps Please 5. Compute the Hamming distance of the following code: 0011010010111100 0000011110001111 0010010110101101 0001011010011110 6. Suppose we are given the following subset of codewords, created for a 7-bit memory word with one parity bit: 11100110, 00001000, 10101011, and 11111110. Does this code use even or odd parity? Explain. 7. Given that the ASCII code for A is 1000001, what is the ASCII code for J? b. Given that the EBCDIC code for A is 1100 0001, what is the EBCDIC code for J? 8. Decode the following ASCII message, assuming 7-bit ASCII characters and no parity: 1001010 1001111 1001000 1001110 0100000 1000100 1001111 1000101LZW algorithm we make two 1000 letter words with the following probabilities for each letter: A: Pb(a)=0.5, Pb(b)=0.2, Pb(c)=0.15, Pb(d)=0.15 B: Pb(a)=0.3, Pb(b)=0.3, Pb(c)=0.25, Pb(d)=0.15 with the lzw algorithm we get compression ratios: A: 8000/2689*100 = 33% B: 8000/2890*100 = 36% Explain what could be the reason behind the differences of compression ratios.