When 24.5 g of NH3 reacts, the actual yield of H20 is 26.5g. What is the percent yield? 4NH3(g) + 6NO (g) -> 5N2(g) + 6H20(l)

Chemistry: Principles and Practice
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Chapter3: Equation, The Mole, And Chemical Formulas
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Problem 3.134QE: A reaction of 43.1 g CS2 with excess Cl2 yields 45.2 g CCl4 and 41.3 g S2Cl2. What is the percent...
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When 24.5 g of NH3 reacts, the actual yield of H20 is 26.5g. What is the percent yield?

4NH3(g) + 6NO (g) -> 5N2(g) + 6H20(l)

 

Expert Solution
Step 1

Given 

mass of NH3    = 24.5 gram 

Actual yield     =   26.5 gram 

℅ yield            =   ?

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