Question
Asked Mar 21, 2019
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When 4.03 g of ammonium perchlorate (NH4ClO4) is dissolved in 120 g of water in a styrofoam calorimeter of negligible heat capacity, the temperature drops from 25.00 to 22.62 °C. Based on this observation, calculate q for the water and ΔH° for the process, assuming that the heat absorbed by the salt is negligible.

NH4ClO4(s) -----> NH4+(aq) + ClO4-(aq)

The specific heat of water is 4.184 J °C-1 g-1.

Give the answers in kJ.

qH2O=

ΔH°=

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Expert Answer

Step 1

Heat energy (q) is calculated by,

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Step 2

Calculate the value of qH2O for the given process,

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Step 3

Standard enthalpy change of a...

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Chemical Thermodynamics

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