Which of the following electrons will experience the greater effective nuclear charge? the electrons in the n = 2 shell in Al the electrons in the n = 2 shell in B Which will be closer to the nucleus? Explain. The electrons in the n = 2 shell in Al, because the radius of Al is smaller than the radius of B. The electrons in the n = 2 shell in Al, because Al experiences a greater effective nuclear charge. The electrons in the n = 2 shell in B, because B experiences a greater effective nuclear charge. The electrons in the n = 2 shell in B, because the radius of B is smaller than the radius of Al. I know the answers to these question is A for the first question and B for the second, my question is why?
Which of the following electrons will experience the greater effective nuclear charge? the electrons in the n = 2 shell in Al the electrons in the n = 2 shell in B Which will be closer to the nucleus? Explain. The electrons in the n = 2 shell in Al, because the radius of Al is smaller than the radius of B. The electrons in the n = 2 shell in Al, because Al experiences a greater effective nuclear charge. The electrons in the n = 2 shell in B, because B experiences a greater effective nuclear charge. The electrons in the n = 2 shell in B, because the radius of B is smaller than the radius of Al. I know the answers to these question is A for the first question and B for the second, my question is why?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter7: Atomic Structure And Periodicity
Section: Chapter Questions
Problem 158AE: An ion having a 4+ charge and a mass of 49.9 u has 2 electrons with principal quantum number n = 1.8...
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Which of the following electrons will experience the greater effective nuclear charge?
the electrons in the n = 2 shell in Al
the electrons in the n = 2 shell in B
Which will be closer to the nucleus? Explain.
The electrons in the n = 2 shell in Al, because the radius of Al is smaller than the radius of B.
The electrons in the n = 2 shell in Al, because Al experiences a greater effective nuclear charge.
The electrons in the n = 2 shell in B, because B experiences a greater effective nuclear charge.
The electrons in the n = 2 shell in B, because the radius of B is smaller than the radius of Al.
I know the answers to these question is A for the first question and B for the second, my question is why?
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