would be the solubility product constant (Ksp) equation for a theoretical compound X2Y3? Provide your solution. a. Ksp = ½ [X²⁺] ⅓ [Y⁻] b.Ksp = 3 [X²⁺] 2

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Problem 126AP: You pour 150.0 mL of a 0.250 M lead(ll) nitrate solution into an empty 500-mL flask. What is the...
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What would be the solubility product constant (Ksp) equation for a theoretical compound X2Y3? Provide your solution.

a. Ksp = ½ [X²⁺] ⅓ [Y⁻]

b.Ksp = 3 [X²⁺] 2 [Y⁻]

c. Ksp = [X²⁺]3 [Y⁻]²

d. Ksp = [X²⁺]2 [Y⁻]3

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