Write a Python function that returns the nth Fibonacci number, where n is an integer passed as a parameter to the function.

For function log, write the missing base case condition and the recursive call. This function computes the log of n to the base b. As an example: log 8 to the base 2 equals 3 since 8 = 2*2*2. We can find this by dividing 8 by 2 until we reach 1, and we count the number of divisions we make. You should assume that n is exactly b to some integer power. Examples: log(2, 4) -> 2 and  log(10, 100) -> 2   public int log(int b, int n ) {  if <<Missing base case condition>> {    return 0;  } else {    return <<Missing a Recursive case action>>  }}

Need help with this python recursive basic pathfinding question. I have the layout of the code but I need help filling in the parts that say "pass" and I need the output of the code to match the sample run below. Our goal is to find a path (not the best path, but just any path) from A to Z.  You see that the green path is not the shortest but it does let us navigate from start to finish.  (The picture below) First, we need to know A and Z, our starting and ending points.  We'll pass these into our function.   I'm going to use a dictionary to represent this graph.  Each node (vertex, circle) will have a name, in this case "A" and "Z" were the names of the nodes, but in the generated maps I'm going to use "Node 1", "Node 2", "Node 3", etc.     Here is an example web_map web_map = { 'Node 1': ['Node 3', 'Node 2'],  'Node 2': ['Node 1', 'Node 4'],  'Node 3': ['Node 1'],  'Node 4': ['Node 2'] } Node 1 is connected to 2 and 3 for instance, and then also note that Node 3 is connected back to…

Please right your own code with some commentary.