
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Transcribed Image Text:Write Matlab program to find secrecy and
authentication of message using RSA
algorithm.
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- Note: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. Consider the LFSR represented by the polynomial x4+x2+1x4+x2+1. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 010101 to represent p5=0,p4=1,p3=0,p2=1,p1=0,p0=1p5=0,p4=1,p3=0,p2=1,p1=0,p0=1).arrow_forwardHelp with this pleasearrow_forwardWe discussed in the lecture that using one-time pad, if the plaintext is made of 0’s, theciphertext will be equal to the key, which is random.What is the pattern of the ciphertext of one-time pad cipher in each of the following cases? (for each case, show an example with all steps and specify for each case whether the resulted ciphertext is random or not):a. The plaintext is made of 1’s (e.g. 11111111111…).b. The plaintext is made of alternating 0’s and 1’s (e.g. 0101010101…)c. The plaintext is a random string of bits.arrow_forward
- What is the output of the first round of the DES algorithm when the plaintextand the key are both all ones? SHOW THE WORKarrow_forwardPlease identify the correct statement(s) for operation modes. IVs can be sent from the sender to the receiver in plaintext. In other words, it is OK for IVs to be visible to the attacker. If two plaintexts are the same, their ciphertexts after CBC will be the same if CBC uses a constant value for IV (i.e., the IV value does not change). If two plaintexts are the same, their ciphertexts are ECB will be the same. It is secure for CFB to reuse IVs for efficiency improvement.arrow_forwardONLY THE TAP BITS. The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m=4m=4.The plaintext given by 01001011=x0x1x2x3x4x5x6x701001011=x0x1x2x3x4x5x6x7 when encrypted by the LFSR produced the ciphertext 11010110=y0y1y2y3y3y5y6y711010110=y0y1y2y3y3y5y6y7. What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent p3=0,p2=1,p1=0,p0=1p3=0,p2=1,p1=0,p0=1).arrow_forward
- Let's pretend a Vigen'ere cipher was used to encrypt a long string of text, and that the encrypted text included many instances of the same string. Describe the methods you'll use to calculate the length of the key based on this information.arrow_forwardA block cipher with a random key is most like a Choose one: Private random function Public random permutation Private random permutation Public random functionarrow_forwardShow all of the steps needed to encrypt and decrypt the ASCII message “YES” without a modular arithmetic calculator in an RSA cipher with public key (143, 7).arrow_forward
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