Write the RISC-V assembly code to implement the following C code as an atomic “set max” operation using the lr.d/sc.d instructions. Here, the argument shvar contains the address of a shared variable which should be replaced by x if x is greater than the value it points to: void setmax(int* shvar, int x) { // Begin critical section if (x > *shvar) *shvar = x; // End critical section } }

Write the assembly code for the safe_input function in the C program given below. Name the file as safeinputfile.asm. #include <stdio.h> int safe_input(char *buffer, unsigned length ); int main(){    char buffer[32];     printf("Your name: ");    fflush(stdout);    safe_input(buffer,32);    printf("Pleased to meet you, %s!\n",buffer);     return 0;}

Please your code should be in mips assembly language

Consider: struct S7 { short m1; short m2; short m3; int m4 [12]; struct S7*next; }; int find_m4 (struct S7*p, int i) { return (&(p->m4[i])); } If we wrote find_m4() in x86-64 assembler, which instruction returns the correct value? O movl 8(%rdi, %rsi,4), %eax movq 6(%rdi, %rsi,8), %rax leaq 8(%rdi, %rsi,4), %rax leal 6(%rdi, %rsi,4), %eax None of these

Implement nibble_swap() function. Take in 4 byte integer and returns integer with swapped nibbles in first two bytes. Use a 3 bit register. The template below is for your reference. The code in the Assembly code portion needs to be completed in Assembly x86-64 #include extern "C" int nibble_swap(int var); int main(int avgc, char** avgs) { int v = nibble_swap(0xCAFEBABA); //answer: 0xACEFABAB printf("Swapped Variable is : 0%X \n", v); return 0; } ----------------Assembly Code --------------------------- ;yasm -f elf64 var.asm section .text global start : ;put ur code here ret

s. Convert the following C code to assembly language using vector operations. (Just do your best, make necessary assumptions, don't worry about syntax too much.) for (i-0;i <300; i++) { c_re[i] = a_re[i] b_re[i]-a_im[i] * b_im[i]: c_im[i] - a_re[i] b_im[i]+a_im[i] * b_re[i];

Write the following C code in MIPS assembly, assume that all of result, in1 and in2 arrays are of double type, also assume var is a double type constant. for( i=0, i<100, i++) result[i] = in1[i]*in2[i] + var; %3D Also explain it well . Thank you!!

The program below uses pointer arithmetic to determine the size of a 'char'variable. By using pointer arithmetic we can find out the value of 'cp' and thevalue of 'cp+1'. Since cp is a pointer, this addition involves pointer arithmetic:adding one to a pointer makes the pointer point to the next element of the sametype.For a pointer to a char, adding 1 really just means adding 1 to the address, butthis is only because each char is 1 byte.1. Compile and run the program and see what it does.2. Write some code that does pointer arithmetic with a pointer to an int anddetermine how big an int is.3. Same idea – figure out how big a double is, by using pointer arithmetic andprinting out the value of the pointer before and after adding 1.4. What should happen if you added 2 to the pointers from exercises 1through 3, instead of 1? Use your program to verify your answer.#include <stdio.h>int main( ){ char c = 'Z'; char *cp = &c; printf("cp is %p\n", cp); printf("The character at cp is…

Have a question requiring an answer in assembly language

Please written by computer source