You attach one end of a spring with a force constant k - 773 N/m to a wall and the other end to a mass m = 2.22 kg and set the mass-spring system into oscillation on a horizontal frictionless surface as shown in the figure. To put the system into oscillation, you pull the block to a position x,- 7.36 cm from equilibrium and release it. (a) Determine the potential energy stored in the spring before the block is released. (b) Determine the speed of the block as it passes through the equilibrium position. m/s (c) Determine the speed of the block when it is at a position x/4. m/s

Q: 20.0° has a spring of force constant k = 480 N/m fastened securely at the bottom so that the spring…

A: Let m be the mass of the block, d be the distance between the uncompressed spring and block, v be…

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A: Total mechanical energy of the system is sum of kinetic energy and potential energy. T.E = K.E…

Q: h one end of a spring with a force constant k = 753 N/m to a wall and the other end to a mass  m =…

A: Givenk=753 N/mm=1.42 kgxi=6.56 cm=0.0656 m

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A: Mass (m) = 2 g = 0.002 kg Extension in the spring's length = 1.7 cm = 0.017 m

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Q: A 0.20-kg mass is hung from a vertical spring of force constant 55 N/m. When the spring is released…

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Q: You attach one end of a spring with a force constant k = 873 N/m to a wall and the other end to a…

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A: Potential at a given point is 12kx2 kinetic energy at that point =12kA2-x2

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Q: A 0.20−kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a…

A: givenm=0.2 kgAt 2.3 cm from equillibriumKinetic energy ,(KE)=1.5 JPotential energy ,(PE)=2.3 J

Q: A 1.68 kg block is held in place against the spring by a 39 NN horizontal external force. The…

A: Since the surface up to B is frictionless till the point B block moves with a velocity 2.1 m/s.Then…

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A: The spring constant is, k=130 N/m The amplitude of the system is, A=0.08 m The block's mass is,…

Q: A block of mass 2 kg is attached to the end of a spring of force constant 180 kN/m as in fig. (a).…

A: Given data The mass of the block is m=2 kg The spring constant is K=180 kN/m The amplitude of the…

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A: Answer: The correct option is D) Minimum Potential Energy. Explanation: The potential Energy of a…

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Q: a) Find the the work required to stretch the spring.   (b) Find the speed the block has as it…

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Q: what is its speed (in m/s) when it is a distance of 10 cm from the equilibrium position

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Q: A block of mass m = 2.00 kg is attached to a spring of force constant k = 5.30 x 102 N/m that lies…

A: a)Work done to stretch the spring = (1/2)(K)(displacement)2  = (1/2)(530)(0.048)2 W =0.61 Joules

Q: A horizontal block-spring system with the block on a frictionless surface has total mechanical…

A: Dear student,                      According to the expert guidelines I am allowed to answer only…

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A:

Q: An ?=20.0 g object is held against the free end of a spring of constant ?=25.0 N/m that is…

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Q: What the total mechanical energy of the system

A: Answer is 0.384  Joules  Explanation is in next step.

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Q: 1.0 0.- E 0.8- 0.7 0.6- 0.5- 0.4- 0.3- 0.2- 0.1- 4 5 6 i 8 Time (s) 1 2 3 A student attaches a block…

A: The maximum kinetic energy represents the total energy of the system

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Q: If we double the spring constant of a horizontal frictionless spring with an attached oscillating…

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Q: ong spring with spring constant 224 N/m has a mass 1.4 kg attached to it, and it can oscillate on a…

A: Given Length of spring, L=50 cm=0.5 mspring constant, k=224 N/mMass attached, m=1.4 kgspring is…

Q: A 0.20−kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a…

A: for spring the total energy of the system is const,KE+PE=const.12mvi2+12kxi2=12mvf2+12kxf2

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A: Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.