~60°C trial ~50°C trial ~40°C trial ~30°C trial ~20°C trial Vol. of HCl used (mL) 19.87 12.93 12.37 9.03 6.30 Moles of HCI used (mol) 9.94 6.47 6.19 4.52 3.15 Moles of borate present (mol) [Borate] (M) Ksp In(Ksp) 1/T (K-1)
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- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…Chemistry The levels of an organic pollutant (P) in the groundwater at the perimeter of a plant were a cause for concern. A 10 mL sample of the water was taken and the pollutant was extracted with 95% efficiency using 25 mL of diethyl ether. GC was used to analyse the concentration of P in diethyl ether. A calibration curve was plotted for a series of standards of P which yielded the following results: Peak Area Toluene Conc. (µg/ml) 12,000 2.6 23,700 5.0 35,500 7.7 46,800 9.9 31,250 Sample Determine the concentration of P in ppb in the initial groundwater sample.
- Amylum, commonly known as starch is a white powder with variable molecular formula due to the different number of repeating sugar units based on the plant that it is obtained from. A sample of amylum in the form of spherical beads was subjected to series of analyses to determine physicochemical properties in the quality control unit of a factory. From the results each bead is found to have a 4.5 mL volume and 1.47 g/mL density. 4 of the beads were placed in a reaction chamber combusted, as a result, 43.1 g CO2 and 14.7 g H2O were obtained. If the molecular weight of the amylum is 972.84 g/mol how many repeating units the starch molecule consist and what is the molecular formula of the starch? [Empirical Formula=CxHyOz, Repeating unit=n, Molecular Formula=( CxHyOz)*n= CnxHnyOnz]Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Q) water hardness of each trial and average ppm with calculation, please. Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.88ml 0.84ml 0.85ml Volume of EDTA Consumed 0.12ml 0.16ml 0.15ml Water Hardness ppm CaCO3 Average ppm
- Downvoted for wrong solution. A river is carrying water containing 2000 mg/l Magnesium Chloride into a small lake. The lake has a naturally occurring Magnesium Chloride of 50 mg/l. If the river flow is 2500 Lmin and the lake flow rate is 1.5 m³.sec¹, what is the concentration of MgCl2 in the lake after the discharge point? Assume that the flows in the river and lake are completely mixed, that the salt is a conservative substance, and the system is at steady state.NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,kIf 35,000 kg of whole milk containing 4% fat is to be separated in a 6-hour period into skim milk with 0.45% fat and cream with 45% fat, what are the mass flow rates of the two output streams from a continuous centrifuge which accomplishes this separation? (Ans; Cream=464.8335kg/h, Skim milk= 5368.4998kg/h)
- Which statements are TRUE regarding internal standards? I. The response factor is calculated by using a mixture containing known amounts of analyte and internal standard and by using detector response to the analyte and the internal standard. II. Internal standards are useful where instrument response or quantity of sample analyzed varies over time. III. Detector response is inversely proportional to concentration. IV. Detector response to analyte and internal standard is assumed to be constant over a range of concentrations A. I, II, and III B. II, III, and IV C. I and II D. I, II, and IVVarious parameters in a gas absorption experiment are as follows; Water flow rate =5 L/min, Air flow rate=25 L/min, CO2 flow rate=6 L/min. Then, to find the amount of CO2 absorbed into the water 1 hour after the system is started and stabilized, 50 mL samples are taken from the inlet and outlet of the tank and titrated with 0.01M NaOH. 100mL samples are taken from the tower entrance and exit and sent to the hemp apparatus. The consumptions measured with the help of the Hemp apparatus are 2.1 mL (inlet) and 1.9 mL (output), respectively. According to this, find the amount of CO2 absorbed by titration? (Note: The relative error in the experiment is 10.)Express [O3] = 2.0 x 1012 molecules cm-3 as a volume mixing ratio (ppbv) at 25 ºC, 1 atm.