Chapter 1, Problem 1.12.2E

Explanation of Solution

Given,

The processor P1 includes clock rate of 4 GHz with 0.9 Cycles Per Instructions (CPI) and requires $\text{5}\text{×}{\text{10}}^{\text{9}}$ number of instructions.

The processor P2 includes clock rate of 3 GHz with 0.75 CPI and requires $1\text{×}{\text{10}}^{\text{9}}$ number of instructions.

The time taken by the processor to complete the process can be calculated using the following formula is given below:

$\text{Time taken}\text{=}\frac{\text{Number}\text{of}\text{instructions}\text{×}\text{CPI}}{\text{Clock}\text{rate}}$

Substitute, “$1\text{×}{\text{10}}^{\text{9}}$” for “Number of instructions”, “0.9” for “CPI” and “$\text{4}\text{×}{\text{10}}^{\text{9}}$” for “clock rate” in the above formula is given below:

$\begin{array}{c}\text{T(P1)}\text{=}\frac{1\text{×}{\text{10}}^{\text{9}}\text{×}\text{0}\text{.9}}{\text{4}\text{×}{\text{10}}^{\text{9}}}\\ \text{=}0.225\end{array}$

Thus, the time required by the processor P1 is “0