![EBK PRECALCULUS: MATHEMATICS FOR CALCUL](https://www.bartleby.com/isbn_cover_images/9781133715047/9781133715047_largeCoverImage.gif)
Concept explainers
(a)
To sketch: The points P and Q in the coordinate plane.
(a)
![Check Mark](/static/check-mark.png)
Explanation of Solution
The given points is
In point
The coordinate plane of two given points is shown below,
Figure (1)
Figure (1) shows the points
(b)
To find: The distance between
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 17T
The distance between P and Q is
Explanation of Solution
Given:
The points is
Calculation:
The distance formula of two points
Where,
Substitute 5 for
Thus, the distance between P and Q is
(c)
To find: The midpoint of line segment PQ.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 17T
The midpoint of segment PQ is
Explanation of Solution
Given:
The points is
Calculation:
The formula of line segment from
Substitute 5 for
Thus, the midpoint of segment PQ is
(d)
To find: The slope of line passes through two pints P and Q.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 17T
The slope of line PQ is
Explanation of Solution
Given:
The points is
Calculation:
The formula of slope of line passes through two points is,
In above formula m is slope of line and
Substitute 6 for
Thus, the slope of line PQ is
(e)
To find: The perpendicular bisector of line PQ.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 17T
The equation of perpendicular bisector is
Explanation of Solution
Given:
The points is
Calculation:
The slope of line passes through points
The lines are perpendicular if,
Where,
Substitute
The slope
The formula of
Substitute
Thus, the equation of perpendicular bisector is
(f)
To find: The equation of circle with diameter PQ.
(f)
![Check Mark](/static/check-mark.png)
Answer to Problem 17T
The equation of circle is
Explanation of Solution
Given:
The points is
Calculation:
The equation of circle with center
The distance between points
The radius of circle is half of diameter that is,
The line segment PQ is a diameter of circle and the midpoint of line segment PQ is center of circle that is
Substitute 1 for h,
Thus, the equation of circle is
Chapter 1 Solutions
EBK PRECALCULUS: MATHEMATICS FOR CALCUL
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781285741550/9781285741550_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134438986/9780134438986_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134763644/9780134763644_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781319050740/9781319050740_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780135189405/9780135189405_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337552516/9781337552516_smallCoverImage.gif)