The temperatures in the given units are to be converted in degree Celsius or Fahrenheit. Concept Introduction: The temperature in degree Celsius can be converted to Fahrenheit as follows: ∘ F = 9 ∘ F 5 ∘ C × ( ∘ C ) + 32 ∘ F The temperature in Fahrenheit can be converted to degree Celsius as follows: ∘ C = 5 ∘ C 9 ∘ F ( ∘ F − 32 ∘ F )

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Answer 1

Question

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

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Answer 2

Question

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

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Answer 3

Question

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

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Answer 4

Question

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

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Answer 5

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

Answer 6

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

Answer 7

Chapter 1, Problem 25QP

Interpretation Introduction

Interpretation: The temperatures in the given units are to be converted in degree Celsius or Fahrenheit.

Concept Introduction:

The temperature in degree Celsius can be converted to Fahrenheit as follows:

∘F=9∘F5∘C×(∘C)+32∘F

The temperature in Fahrenheit can be converted to degree Celsius as follows:

∘C=5∘C9∘F(∘F−32∘F)

Answer 8

Expert Solution & Answer

Answer to Problem 25QP

Solution:

a)

35∘C

b)

−11∘C

c)

39∘C

d)

1011∘C

e)

−459.67∘F

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

a) 95∘F, the temperature on a hot summer day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(63∘F)=35∘C

Therefore, the temperature in degree Celsius is 35∘C.

b) 12∘F, the temperature on a cold winter day.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(95∘F−32∘F)=5∘C9∘F×(−20∘F)=−11.11∘C

Therefore, the answer is −11.11∘C, which rounds off to −11∘C.

c) 102∘F, fever

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(102∘F−32∘F)=5∘C9∘F×(70∘F)=38.89∘C

Therefore, the temperature is 38.89∘C, which rounds off to 39∘C.

d)A furnace operating at 1852∘F.

The temperature in Fahrenheit can be converted to degree Celsius as:

∘C=5∘C9∘F(∘F−32∘F).

∘C=5∘C9∘F(1852∘F−32∘F)=5∘C9∘F×(1820∘F)=1011.11∘C

Therefore, the temperature is 1011.11∘C which rounds off to 1011∘C.

e) −273.15∘C (Theoretically the lowest attainable temperature).

The temperature in Fahrenheit can be converted to degree Celsius as:

∘F=9∘F5∘C×(∘C)+32∘F.

F=9∘F5∘C×(−273.15∘C)+32∘F=−491.67∘F+32∘F=−459.67∘F

Therefore, the temperature is −459.67∘F.

Answer 12

Ch. 1.1 - Practice Problem ATTEMPT Express the freezing...Ch. 1.1 - Practice ProblemBUILD According to the website of...Ch. 1.1 - Prob. 1PPC Ch. 1.2 - Prob. 1PPA Ch. 1.2 - Practice ProblemBUILD In Ray Bradbury's 1953 novel...Ch. 1.2 - Practice ProblemCONCEPTUALIZE If a single degree...Ch. 1.3 - Practice ProblemAttempt Given that 25 .0 mL of...Ch. 1.3 - Practice Problem BUILD Calculate (a) the density...Ch. 1.3 - Practice ProblemCONCEPTUALIZE Using the picture of...Ch. 1.3 - The coldest temperature ever recorded on Earth was...

Answer to Problem 25QP

Explanation of Solution

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Chapter 1 Solutions