UNIVERSE LL W/SAPLINGPLUS MULTI SEMESTER
11th Edition
ISBN: 9781319278670
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 1, Problem 31Q
To determine
The distance of the spacecraft in kilometers (using power of ten notation), given that the radio signal from Voyager 2 travelled for 4 hours to reach Earth. The radio signal had a speed equal to that of light.
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Chapter 1 Solutions
UNIVERSE LL W/SAPLINGPLUS MULTI SEMESTER
Ch. 1 - Prob. 1CCCh. 1 - Prob. 2CCCh. 1 - Prob. 3CCCh. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7Q
Ch. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10QCh. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 14QCh. 1 - Prob. 15QCh. 1 - Prob. 16QCh. 1 - Prob. 17QCh. 1 - Prob. 18QCh. 1 - Prob. 19QCh. 1 - Prob. 20QCh. 1 - Prob. 21QCh. 1 - Prob. 22QCh. 1 - Prob. 23QCh. 1 - Prob. 24QCh. 1 - Prob. 25QCh. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - Prob. 31QCh. 1 - Prob. 32QCh. 1 - Prob. 33QCh. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42QCh. 1 - Prob. 43QCh. 1 - Prob. 44Q
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- Earlier in this chapter, we modeled the solar system with Earth at a distance of about one city block from the Sun. If you were to make a model of the distances in the solar system to match your height, with the Sun at the top of your head and Pluto at your feet, which planet would be near your waist? How far down would the zone of the terrestrial planets reach?arrow_forwardDraw a picture that explains why Venus goes through phases the way the Moon does, according to the heliocentric cosmology. Does Jupiter also go through phases as seen from Earth? Why?arrow_forwardAt a given point, venus is 37.5 million miles from the earth. How long does it take for light to leave a source on earth and reach venus? give the answer in seconds. (the speed of light is 2.998x10^8 m/sec and 1 km= 0.62 miles)arrow_forward
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- You land on a strange spherical planet X. As a curious physicist, you set out to make the following measurements: (1) you observe that planet X has no appreciable atmosphere, (2) you measure that if you throw a 0.25 kg stone vertically upwards with launch speed 10 m/s, it comes back to ground in 8 sec, and (3) you measure the equatorial circumference to be 250,000 km. What is the mass of planet X? [Hint: The value of g on the planet surface is related to its mass M and radius R by the formula g = GM/R2.] a) 9*1025 kg b) 2.3*1027 kg c) 6.9*1026 kg If you take your spaceship to a 10,000 km altitude circular orbit around planet X, what would be the orbital period of the spaceship? [Hint: Use the fact that the gravitational force causes the radial acceleration to calculate the orbital speed.] a) 4.89 hrs b) 9.78 hrs c) 19.56 hrsarrow_forwardIf we send astronauts to Mars, there will be a time delay anytime we send or receive messages to them here on Earth. Given that Mars is an average of 54.6 million km away from Earth, how long is this time delay for a 2-way 'round-trip' communication - sent to Earth, then back to Mars? (this might be important in emergency situations) answer choices a)About 4 minutes. b)About 30 seconds. c)About 10 seconds. d)About 6 minutes.arrow_forwardIt took astronauts 3 days to reach the moon, which is 384,400km from Earth. Going at the same speed, how much longerwould it take astronauts to reach Mars, which is 0.524 AU fromEarth.arrow_forward
- On August 27, 2003, the planet Mars was at a distance of 0.373 AU from Earth. The diameter of Mars is 6788 km. Calculate the angular diameter of Mars, as seen from Earth on August 27, 2003. Give your answer in arcminutes.arrow_forwardWhy Venus’ phase observation made it very difficult to argue against the heliocentric model.arrow_forwardThe main advantage of taking images of our planet from high-altitude orbits is that you can see a large fraction of the Earth's surface. The main disadvantage is that there will be too many low-altitude satellites obscuring your view of the Earth high-altitude satellites must launch to the west, which is more costly being at high altitude makes your satellite subject to strict international regulations you can't see as much detail in images taken from high altitudearrow_forward
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