Chapter 1, Problem 70P

(a)

To determine

Convert the given measurements in suitable metric prefix form without using scientific notation.

Answer to Problem 70P

Theradius of the Earth in metric prefix form is $\underset{\_}{6\text{Mm}}$.

Explanation of Solution

In this case, the given measurement value is $6\times {10}^6\text{m}$.

Using table 1.2 SI prefixes, convert this scientific notation of ${10}^6$ to metric prefix form of $\text{mega}\left(\text{M}\right)$.

Conclusion:

Conversion,

    $6\times {10}^6\text{m}\times \frac{\text{1}\text{Mm}}{{10}^6\text{m}}=6\text{Mm}$

Therefore, the radius of the Earth in metric prefix form is $\underset{\_}{6\text{Mm}}$.

(b)

To determine

Convert the given measurements in suitable metric prefix form without using scientific notation.

Answer to Problem 70P

The length of a human body is $\underset{\_}{183\text{cm}}$.

Explanation of Solution

In this case, the given measurement value is $6\text{ft}$.

Convert $1\text{ft}$ to metric prefix form of $\text{m}$,

  $1\text{ft}\text{=}\text{0}\text{.3048}\text{m}$.

Conclusion:

Substitute $\text{0}\text{.3048}\text{m}$ for $\text{ft}$ to the given measurement,

    $\begin{array}{c}6\text{ft}\text{=}\text{6}\times \text{0}\text{.3048}\text{m}\\ \text{=}\text{1}\text{.8288}\text{m}\\ \text{=}\text{1}\text{.83}\text{m}\times \frac{100\text{cm}}{1\text{m}}\\ =183\text{cm}\end{array}$

Therefore, the length of a human body is $\underset{\_}{183\text{cm}}$.

(c)

To determine

Convert the given measurements in suitable metric prefix form without using scientific notation.

Answer to Problem 70P

A cell’s diameter is $\underset{\_}{2\text{μm}}$.

Explanation of Solution

In this case, the given measurement value is $2\times {10}^{-6}\text{m}$.

Using table 1.2 SI prefixes, convert this scientific notation of ${10}^{-6}$ to metric prefix form of $\text{micro}\left(\text{μ}\right)$.

Conclusion:

Convert,

    $2\times {10}^{-6}\text{m}\times \frac{{10}^6\text{μm}}{1\text{m}}\text{=}\text{2}\text{μm}$

Therefore, a cell’s diameter is $\underset{\_}{2\text{μm}}$.

(d)

To determine

Convert the given measurements in suitable metric prefix form without using scientific notation.

Answer to Problem 70P

The width of the hemoglobin molecule is $\underset{\_}{3\text{nm}}$.

Explanation of Solution

In this case, the given measurement value is $3\times {10}^{-9}\text{m}$.

Using table 1.2 SI prefixes, convert this scientific notation of ${10}^{-9}$ to metric prefix form of $\text{nano}\left(\text{n}\right)$.

Conclusion:

Convert,

    $3\times {10}^{-9}\text{m}\times \frac{{10}^9\text{nm}}{1\text{m}}=3\text{nm}$

Therefore, the width of the hemoglobin molecule is $\underset{\_}{3\text{nm}}$.

(e)

To determine

Convert the given measurements in suitable metric prefix form without using scientific notation.

Answer to Problem 70P

The distance between two atoms is $\underset{\_}{300\text{pm}}$.

Explanation of Solution

In this case, the given measurement value is $3\times {10}^{-10}\text{m}$ .

Using table 1.2 SI prefixes, convert this scientific notation of ${10}^{-12}$ to metric prefix form of $\text{pico}\left(\text{p}\right)$.

Conclusion:

Convert,

    $\begin{array}{c}3\times {10}^{-10}\text{m}\times \frac{{10}^{12}\text{pm}}{1\text{m}}=3\times {10}^2\text{pm}\\ \text{=300}\text{pm}\end{array}$

Therefore, the distance between two atoms is $\underset{\_}{300\text{pm}}$.