Find the required shear force to cause failure of the specimen.

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1 .For a direct shear test on a dry sand, the following are given:• Specimen size: 75 mm 75 mm 30 mm (height)• Normal stress: 200 kN/m2• Shear stress at failure: 175 kN/m2a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure?in the specime

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Chapter 10, Problem 10.4P

To determine

Find the required shear force to cause failure of the specimen.

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1 .For a direct shear test on a dry sand, the following are given:• Specimen size: 75 mm 75 mm 30 mm (height)• Normal stress: 200 kN/m2• Shear stress at failure: 175 kN/m2a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure?in the specime

The following data are given for a direct shear test conducted on dry sand:- Specimen dimensions: 75 mm X 75 mm X 30 mm (height)- Normal stress: 200 kN/m2- Shear stress at failure: 175 kN/m2a) Determine the angle of friction,b) For a normal stress of 150 kN/m2, what shear force is required to cause failure?

A direct shear test was conducted on a specimen of dry sand with a normal stress of 200 kN/m2. Failure occurred at a shear stress of 175 kN/m2. The size of the specimen testedwas 75 mm × 75 mm × 30 mm (height). Determine the angle of friction, . For a normal stress of 150 kN/m2, what shear force would be required to cause failure of the specimen?