STEEL DESIGN W/ ACCESS
6th Edition
ISBN: 9781337761499
Author: Segui
Publisher: CENGAGE L
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Question
Chapter 10, Problem 10.6.2P
To determine
(a)
Maximum factored concentrated load that can be supported by using LRFD method.
To determine
(b)
Maximum factored concentrated load that can be supported by using ASD method.
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The details of an end bearing stiffener are shown in Figure . The stiffener plates are 9⁄16-inch thick, and the web is 3⁄16-inch thick. The stiffeners are clipped 1⁄2 inch to provide clearance for the flange-to-web welds. All steel is A572 Grade 50. a. Use LRFD and determine the maximum factored concentrated load that can be supported. b. Use ASD and determine the maximum service concentrated load that can be supported.
Determine the maximum service load, P, that can be applied if the live load-to-dead load ratio is 2.0. Each component is a PL 3⁄4 x 7 of A242 steel. The weld is a 1⁄2-inch fillet weld, E70 electrode. a. Use LRFD. b. Use ASD.
The plate with dimension 18 mm x 400 mm (thickness by width) is to be connected to a
gusset plate using 6-Ø24 mm bolts in arrange in 3 row (2 each row) along the x-axis. The
plate is to be design for tension. Using A36 steel and assuming Ae= An. Use NSCP 2015.
a. Compute the design strength considering yielding and tensile rupture. (LRFD)
b. Compute the allowable strength considering yielding and tensile rupture. (ASD)
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- Use an elastic analysis and determine the maximum load in the weld (in kips per inch of length).arrow_forwardSituation 5. The angular section shown below is welded to a 12 mm gusset plate. Both materials are A36 steel with Fy = 250 MPa. The allowable tensile stress is 0.6Fy. The weld is E80 Electrode and 12 mm thickness. INNOVATIONS Properties of L 150x90x12: y = 50 shear stress of weld = 0.3Fu A = 2750 Allowable REVIEW INNOVATIE a K ➜ www A. 234 KN B. 349 KN b 13. What is the value of P without exceeding the allowable tensile the angle? C. 382 kN p. 413 kN 14. Find required length of the weld based on shear? A. 280 mm C. 300 mm D. 380 mm B. 320 mm 15. Find the required value of a? A. 108 mm B. 97.9 mm D. 185 mm NEW INNOVATIONS REVIEW INNOVATIOf REVIEW NEW INNOVATIONSarrow_forwardThe plate with dimension 18 mm x 400 mm (thickness by width) is to be connected to a gusset plate using 6-Ø24 mm bolts in arrange in 3 row (2 each row) along the x-axis. The plate is to be design for tension. Using A36 steel and assuming A= An. Use NSCP 2015. a. Compute the design strength considering yielding and tensile rupture. (LRFD} b. Compute the allowable strength considering yielding and tensile rupture. (ASD)arrow_forward
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