MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
MindTap Engineering, 1 term (6 months) Printed Access Card for Das/Sivakugan’s Principles of Foundation Engineering, 9th
9th Edition
ISBN: 9781337705202
Author: Das, Braja M., SIVAKUGAN, Nagaratnam
Publisher: Cengage Learning
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Chapter 10, Problem 10.9P

A plate loading test was carried out on a medium dense sand, using a 1 ft wide square plate, and k1 was determined as 350 lb/in3. Determine the coefficient of subgrade reaction for a 7.5 ft wide square foundation and a 7.5 ft × 10.5 ft rectangular foundation.

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A plate loading test was carried out on a medium dense sand, using a 300 mm wide square plate, and ko.3 was deter- mined as 100 MN/m³. Determine the coefficient of subgrade reaction for a 2.5 m wide square foundation and a 2.5 m X 3.5 m rectangular foundation.
In a geotechnical laboratory an oedometer test on a saturated clay soil was conducted. The results in the laboratory report stated that the Cc = 0.2, Cr = 0.04 and OCR = 4.5. The existing vertical effective stress in the field was 130 kPa. A building foundation was designed to construct above the soil condition. This will increase the vertical stress at the center of the clay by 150 kPa. The thickness of the clay layer is 2 m and its water content is 28%. Solve the primary consolidation settlement and determine the difference in the settlement if OCR value were 1.5 instead 4.5.
Question 3 a) In a geotechnical laboratory an oedometer test on a saturated clay soil was conducted. The results in the laboratory report stated that the Ce= 0.2, C, -0.04 and OCR = 4.5. The existing vertical effective stress in the field was 130 kPa. A shallow foundation was designed to construct above the soil condition. This will increase the vertical stress at the center of the clay by 50 kPa. The thickness of the clay layer is 2 m and its water content is 28%. Solve the primary consolidation settlement and determine the difference in the settlement if OCR value were 1.5 instead 4.5.
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