The voltage across a 10
a. On a practical basis, how much time must pass before the charging phase has passed?
b. What is the resistance of the circuit?
c. What is the voltage at
d. What is the voltage at 10 time constants?
e. Under steady-state conditions, how much charge is on the plates?
f. If the leakage resistance is 1000 M
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EBK INTRODUCTORY CIRCUIT ANALYSIS
- Consider an LRC series circuit with a resistance of 2.5 ohms, capacitance of 0.1 farad, aninductance of 0.1 henry and electromotive force, volts. Given thatAssume there is no initial charge and no initial current on thecapacitor.The equation of the charge q(t), on the capacitor at any time t q(t)=C1e−5t+C2e−20t+0.05cost+0.2sint . (Do not solve the coefficients). a) State the equation of the current, i(t). b) State the transient and the steady-state current. c) What is the current after a long time.arrow_forwardA)Just after the switch is closed, what is the magnitude of the potential difference Vab across the resistor R1? B)Magnitude of the potential difference Vcd across the inductor L? C)The switch is left closed a long time then opened. Just after the switch is opened, what is the magnitude of the potential difference Vab across the resistor R1? D)What is the magnitude of the potential difference Vcd across the inductor L?arrow_forward2. A parallel plate capacitor with a plate area of 0.13 square meters separated by 1 mm is charged to 9 Volts by a battery, which is then disconnected. The plate separation is then increased to 40 mm.A. Using the expression for the capacitance of a parallel plate capacitor, what do you expect the new potential difference across the plates to be after the increase?B. Suppose you measure the potential difference across the plates after the separation and find it to be 30 V (this should be very different from what you found in part A). This unexpected result can be explained by the effects of “stray capacitance” with nearby objects. Assuming that the stray capacitance can be modeled as a capacitor connected in parallel with the parallel plate capacitor, find the value of this stray capacitance.arrow_forward
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- Derive an expression for the electrical energy stored in a capacitor of capacitance C when charged to a potential difference V. If C = 2µF and V= 4V, calculate(l.) the final energy stored in the capacitor,(II.) the work done by the battery in the charging process Account for any difference between your answers in parts (I) and (II) abovearrow_forwardGiven the capacitance of four capacitors Ca= 30 µF, Cb = 20 µF, Cc = 40 µF and Cd = 10 µF. If Cb and Cc are connected in parallel and the parallel combination is connected in series with Ca and the combination is further connected in parallel with Cd, calculate (a) the equivalent capacitance (b) the voltage across each capacitor if the circuit is supplied by 240 volts DC source (c) the charge on each capacitor.arrow_forwardA capacitor consists of two circular plates of radius a separated by a distance d (assume d << a). The centre of each plate is connected to the terminals of a voltage source by a thin wire. A switch in the circuit is closed at time t = 0 and a current I(t) flows in the circuit. The charge on the plate is related to the current according to I (t) = dq/dt. We begin by calculating the electric field between the plates. Throughout this problem you may ignore edge effects. We assume that the electric field is zero for r > a. (A) Use Gauss’ Law to find the electric field between the plates as a function of time t, in terms of q(t), a, ε, and π. The vertical direction is the k (b) Now take an imaginary flat disc of radius r < a inside the capacitor, as shown below. Using your expression for E above, calculate the electric flux through this flat disc of radius r < a in the plane midway between the plates, in terms of r, q(t), a, and ε. (C) Calculate the Maxwell…arrow_forward
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