21ST CENT.AST.W/WKBK+SMARTWORK >BI<
21ST CENT.AST.W/WKBK+SMARTWORK >BI<
6th Edition
ISBN: 9780309341523
Author: Kay
Publisher: NORTON
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Chapter 10, Problem 37QP
To determine

The polar radius of the Jupiter.

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The International Space Station is about 90 meters across and about 380 kilometers away.  One night it appears to be the same angular size as Jupiter.  Jupiter is 143,000 km in size.  Use S = r x a to figure out how far away Jupiter is in AU.  Note 1 AU = 1.5 x 108 km
A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.
The value we have just calculated is the combined masses of Jupiter and Callisto!  Their mass is in units of the Sun's Mass (MS) - we can convert this to units which are more familiar to us like kilograms by multiplying this answer by the scale factor (1.99x1030 kg/1 MS):  (MJupiter + MCallisto)   =   (               MS) (1.99x1030 kg/1 Solar Mass)  =   _______x_10___ kg (I have already written the x 10 so you are reminded to write the exponenet of 10 in the scientific notation expression of your answer).  Since you know from looking at pictures of Jupiter with its Galilean Satellites (look in your book at a picture if you have not already), that Callisto is much smaller than Jupiter - in fact it is less than 0.001 of Jupiter's size or mass, so the number we have just calculated for (MJupiter + MCallisto) is almost the same as MJupiter .  How much more massive is Jupiter than the Earth? (The mass of Earth is about 5.98 x 1024 kg)
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