Explanation Given: Gauge pressure = Total pressure − atmospheric pressure [Here atmospheric pressure = 14.7 psi] Maximum rating of an automobile tire = 38.0 psi At a temperature of 12.0° C or (12+273.15) K = 285.15 K, Volume of a tire = 11.8 L Gauge pressure of the tire = 36 psi Total pressure = (36 + 14.7) psi = 50.7 psi At a temperature of 65.0° C or (65 + 273.15) = 338.15 K, Volume of the tire = 12.2 L Formula used: According to ideal gas law , PV = nRT Here, P = pressure of a gas V = volume of the gas n = moles of the gas R = gas constant T = temperature of the gas in Kelvin scale Calculation: At a temperature of 285.15 K, V = volume of gas in the tire = 11.8 L P = pressure of gas =50.7 psi = (50.7×0.068) atm =3.45 atm [Since 1 psi = 0.068 atm] R = gas constant = 0.082 L.atm/K.mol n = moles of gas inside the tire =? PV = nRT P = P V R T = ( 3 . 45 a t m ) × ( 11 . 8 L ) ( 0 ...

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Question

Chapter 10, Problem 43E

Interpretation Introduction

To determine: Gauge pressure of a 12.2 L automobile tire at a temperature of 65° C and whether thepressure exceeds its maximum rating.

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Chapter 10 Solutions

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