(a)
The time to make each orbit and gravitational force on the object
Answer to Problem 64QAP
Time taken for each orbital
Explanation of Solution
Given info:
Altitude =
Mass of the object =
Formula used:
Calculation:
Time taken for each orbital,
Conclusion:
Time taken for each orbital
(b)
Gravitational force on the object
Answer to Problem 64QAP
Gravitational force
Fraction
Explanation of Solution
Given info:
Altitude =
Mass of the object =
Formula used:
Calculation:
Gravitational force,
Conclusion:
Gravitational force
Fraction
(c)
How can an object be considered weightless in ISS?
According to the calculation comparatively to the weight on Earth, in the ISS weigh of the object is less.
Given info:
Altitude =
Mass of the object =
Explanation:
Comparatively to the weight on Earth, in the ISS weigh of the object is less.
Conclusion:
Comparatively to the weight on Earth, in the ISS weigh of the object is less.
Answer to Problem 64QAP
According to the calculation comparatively to the weight on Earth, in the ISS weigh of the object is less.
Explanation of Solution
Given info:
Altitude =
Mass of the object =
Comparatively to the weight on Earth, in the ISS weigh of the object is less.
Conclusion:
Comparatively to the weight on Earth, in the ISS weigh of the object is less.
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Chapter 10 Solutions
COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
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- A car of mass 1 230 kg travels along a circular road of radius 60.0 m at 18.0 m/s. (a) Calculate the magnitude of the cars centripetal acceleration. (b) What is the magnitude of the force of static friction acting on the car? (See Section 7.4.)arrow_forwardIf you release a ball while inside a freely falling elevator, the ball remains in front of you rather than falling to the floor because the ball, the elevator, and you all experience the same downward gravitational acceleration. What happens if you repeal this experiment with a helium-filled balloon?arrow_forward
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