   Chapter 10.1, Problem 7E

Chapter
Section
Textbook Problem

Matching In Exercises 5-10, match the equation with its graph. [The graphs are labeled (a), (b), (c), (d), (e). and (f).] y 2 16 − x 2 1 = 1

To determine
The correct match of the equation y216x2=1 with its corresponding graph.

Explanation

Given: The equation y216x2=1 and the graph of equations are,

Calculation: Consider the equation y216x2=1. Since the given equation is of the type x2a2y2b2=1 which is the standard form of the hyperbola and the hyperbola has a center at (h,k) that (0,0) with semi axis a=4 and semi conjugate axis b=1

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