Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Chapter 10.3, Problem 12PPS

a.

To determine

To find outliers in the given set of data

a.

Expert Solution
Check Mark

Answer to Problem 12PPS

0.204 is the outlier in the given data set.

Explanation of Solution

Given information: Data set is

0.267, 0.305, 0.304, 0.201, 0.284, 0.302, 0.311, 0.289, 0.300 and 0.292

Calculation:

Sorting data in an ascending order,

0.201, 0.267, 0.284, 0.289, 0.292, 0.300, 0.302, 0.304, 0.305, 0.311

An outlier is an observation that lies an abnormal distance from other values in a random sample from a population. Analysing the given data set.

Hence, Outlier is 0.201. It is because this value is very far away from all data points in the given dataset.

b.

To determine

To calculate range and 5 number summary.

b.

Expert Solution
Check Mark

Answer to Problem 12PPS

The range is 0.110.

The five number summary is 0.201, 0.304, 0.146, 0.289, 0.311

Explanation of Solution

Given information: Dataset is

0.267, 0.305, 0.304, 0.201, 0.284, 0.302, 0.311, 0.289, 0.300 and 0.292

Formula used:

Range= Maximum- minimum

Lower quartile= (N+1)4

Median = (Nth2)ob+(N2+1)thob2

Upper quartile= 3(N+1)4

Where, N is number of tiles/data points

Calculation:

Sorting data in an ascending order,

0.201, 0.267, 0.284, 0.289, 0.292, 0.300, 0.302, 0.304, 0.305, 0.311

Minimum is the lowest value in a dataset. Hence,

Minimum is 0.201

Maximum is the highest value in the dataset. Hence,

Maximum is 0.311

For range, substituting the value in the formula of range,

  Range=0.3110.201

On solving,

  Range=0.110

Hence, range is 0.110

For median, substituting the value in the formula of median,

  =(10th2)ob+(102+1)thob2

On solving,

  =5th+6th2

Substituting the value of 5th and 6th observations,

  =0.292+0.3002

On solving,

  =0.146

Hence, median is 0.146

For Lower quartile, substituting the value,

  =(10+1)th4ob

So,

  =114ob

On solving,

  =2.75

On solving,

  =2.75

On rounding off the value,

  3

Substituting the value,

  Q1=0.284

For Upper quartile, substituting the values,

  =3(10+1)th4ob

So,

  =334thob

On solving,

  =8.25

On rounding off the value,

  8thob

Substituting the value,

  Q3=0.304

The five number summary is 0.201, 0.284, 0.146, 0.304, 0.311

c.

To determine

To identify outlier and find mean and median

c.

Expert Solution
Check Mark

Answer to Problem 12PPS

Outlier is 0.201. Mean is 0.28 and Median is 0.29

Explanation of Solution

Given information: the given dataset is,

0.267, 0.305, 0.304, 0.201, 0.284, 0.302, 0.311, 0.289, 0.300, 0.292Formula used: Median formula is,

Median= (n+1)th2observation

Mean formula is,

Mean= i=1nXin

Where, n=total number of terms,

Calculation:

Sorting data,

0.201, 0.267, 0.284, 0.289, 0.292, 0.300, 0.302, 0.304, 0.305 and 0.311

Total number of data points= 10

Outlier is 0.201

Removing the outlier, now the new data set is

0.267, 0.284, 0.289, 0.292, 0.300, 0.302, 0.304, 0.305, 0.311

Now, the number of data points =9

For median, substituting the values,

= (9+12)thob

On solving,

=5th ob

Substituting the value of 5th observation,

=0.292

Hence, median is 0.292

For mean, substituting the values,

  =0.267+0.284+0.289+0.292+0.300+0.302+0.304+0.305+0.3119

On solving,

  =0.26

Hence, mean is 0.26

d.

To determine

To find lowest batting average.

d.

Expert Solution
Check Mark

Answer to Problem 12PPS

0.267 is the lowest batting average.

Explanation of Solution

Given information: The data set is

0.201, 0.267, 0.284, 0.289, 0.292, 0.300, 0.302, 0.304, 0.305, 0.311

0.201 is an outlier

Analysing the dataset, 0.267 is the first observation after the outlier. Hence, 0.267 is the lowest batting average. As after an outlier, it is least batting average and is close to other batting averages.

Hence, 0.267 is the lowest batting average.

Chapter 10 Solutions

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Ch. 10.1 - Prob. 6CYUCh. 10.1 - Prob. 7PPSCh. 10.1 - Prob. 8PPSCh. 10.1 - Prob. 9PPSCh. 10.1 - Prob. 10PPSCh. 10.1 - Prob. 11PPSCh. 10.1 - Prob. 12PPSCh. 10.1 - Prob. 13PPSCh. 10.1 - Prob. 14PPSCh. 10.1 - Prob. 15HPCh. 10.1 - Prob. 16HPCh. 10.1 - Prob. 17HPCh. 10.1 - Prob. 18HPCh. 10.1 - Prob. 19HPCh. 10.1 - Prob. 20HPCh. 10.1 - Prob. 21HPCh. 10.1 - Prob. 22PFACh. 10.1 - Prob. 23PFACh. 10.1 - Prob. 24PFACh. 10.1 - Prob. 25PFACh. 10.1 - Prob. 26PFACh. 10.1 - Prob. 27PFACh. 10.2 - Prob. 1AGPCh. 10.2 - Prob. 1BGPCh. 10.2 - Prob. 2AGPCh. 10.2 - Prob. 2BGPCh. 10.2 - Prob. 3GPCh. 10.2 - Prob. 4GPCh. 10.2 - Prob. 5GPCh. 10.2 - Prob. 1CYUCh. 10.2 - Prob. 2CYUCh. 10.2 - Prob. 3CYUCh. 10.2 - Prob. 4CYUCh. 10.2 - Prob. 5CYUCh. 10.2 - Prob. 6PPSCh. 10.2 - Prob. 7PPSCh. 10.2 - Prob. 8PPSCh. 10.2 - Prob. 9PPSCh. 10.2 - Prob. 10PPSCh. 10.2 - Prob. 11PPSCh. 10.2 - Prob. 12PPSCh. 10.2 - Prob. 13PPSCh. 10.2 - Prob. 14PPSCh. 10.2 - Prob. 15PPSCh. 10.2 - Prob. 16HPCh. 10.2 - Prob. 17HPCh. 10.2 - Prob. 18HPCh. 10.2 - Prob. 19PFACh. 10.2 - Prob. 20PFACh. 10.2 - Prob. 21PFACh. 10.2 - Prob. 22PFACh. 10.2 - Prob. 23PFACh. 10.2 - Prob. 24PFACh. 10.2 - Prob. 25PFACh. 10.3 - Prob. 1GPCh. 10.3 - Prob. 2GPCh. 10.3 - Prob. 3GPCh. 10.3 - Prob. 4GPCh. 10.3 - Prob. 1CYUCh. 10.3 - Prob. 2CYUCh. 10.3 - Prob. 3CYUCh. 10.3 - Prob. 4CYUCh. 10.3 - Prob. 5PPSCh. 10.3 - Prob. 6PPSCh. 10.3 - Prob. 7PPSCh. 10.3 - Prob. 8PPSCh. 10.3 - Prob. 9PPSCh. 10.3 - Prob. 10PPSCh. 10.3 - Prob. 11PPSCh. 10.3 - Prob. 12PPSCh. 10.3 - Prob. 13PPSCh. 10.3 - Prob. 14PPSCh. 10.3 - Prob. 15HPCh. 10.3 - Prob. 16HPCh. 10.3 - Prob. 17HPCh. 10.3 - Prob. 18HPCh. 10.3 - Prob. 19HPCh. 10.3 - Prob. 20HPCh. 10.3 - Prob. 21PFACh. 10.3 - Prob. 22PFACh. 10.3 - Prob. 23PFACh. 10.3 - Prob. 24PFACh. 10.3 - Prob. 25PFACh. 10.3 - Prob. 26PFACh. 10.3 - Prob. 27PFACh. 10.4 - Prob. 1GPCh. 10.4 - Prob. 2GPCh. 10.4 - Prob. 3GPCh. 10.4 - Prob. 4GPCh. 10.4 - Prob. 1CYUCh. 10.4 - Prob. 2CYUCh. 10.4 - Prob. 3CYUCh. 10.4 - Prob. 4CYUCh. 10.4 - Prob. 5PPSCh. 10.4 - Prob. 6PPSCh. 10.4 - Prob. 7PPSCh. 10.4 - Prob. 8PPSCh. 10.4 - Prob. 9PPSCh. 10.4 - Prob. 10PPSCh. 10.4 - Prob. 11PPSCh. 10.4 - Prob. 12HPCh. 10.4 - Prob. 13PPSCh. 10.4 - Prob. 14PPSCh. 10.4 - Prob. 15PPSCh. 10.4 - Prob. 16PPSCh. 10.4 - Prob. 17PPSCh. 10.4 - Prob. 18PFACh. 10.4 - Prob. 19PFACh. 10.4 - Prob. 20PFACh. 10.4 - Prob. 21PFACh. 10.4 - Prob. 22PFACh. 10.4 - Prob. 23PFACh. 10.5 - Prob. 1GPCh. 10.5 - Prob. 2GPCh. 10.5 - Prob. 3AGPCh. 10.5 - Prob. 3BGPCh. 10.5 - Prob. 4AGPCh. 10.5 - Prob. 4BGPCh. 10.5 - Prob. 1CYUCh. 10.5 - Prob. 2CYUCh. 10.5 - Prob. 3CYUCh. 10.5 - Prob. 4CYUCh. 10.5 - Prob. 5CYUCh. 10.5 - Prob. 6CYUCh. 10.5 - Prob. 7PPSCh. 10.5 - Prob. 8PPSCh. 10.5 - Prob. 9PPSCh. 10.5 - Prob. 10PPSCh. 10.5 - Prob. 11PPSCh. 10.5 - Prob. 12PPSCh. 10.5 - Prob. 13PPSCh. 10.5 - Prob. 14PPSCh. 10.5 - Prob. 15PPSCh. 10.5 - Prob. 16PPSCh. 10.5 - Prob. 17PPSCh. 10.5 - Prob. 18PPSCh. 10.5 - Prob. 19PPSCh. 10.5 - Prob. 20PPSCh. 10.5 - Prob. 21PPSCh. 10.5 - Prob. 22HPCh. 10.5 - Prob. 23HPCh. 10.5 - Prob. 24HPCh. 10.5 - Prob. 25HPCh. 10.5 - Prob. 26PFACh. 10.5 - Prob. 27PFACh. 10.5 - Prob. 28PFACh. 10.5 - Prob. 29PFACh. 10.6 - Prob. 1AGPCh. 10.6 - Prob. 1BGPCh. 10.6 - Prob. 1CGPCh. 10.6 - Prob. 1DGPCh. 10.6 - Prob. 2GPCh. 10.6 - Prob. 3AGPCh. 10.6 - Prob. 3BGPCh. 10.6 - Prob. 4AGPCh. 10.6 - Prob. 4BGPCh. 10.6 - Prob. 4CGPCh. 10.6 - Prob. 4DGPCh. 10.6 - Prob. 5AGPCh. 10.6 - Prob. 1CYUCh. 10.6 - Prob. 2CYUCh. 10.6 - Prob. 3CYUCh. 10.6 - Prob. 4CYUCh. 10.6 - Prob. 5CYUCh. 10.6 - Prob. 6CYUCh. 10.6 - Prob. 7CYUCh. 10.6 - Prob. 8CYUCh. 10.6 - Prob. 9CYUCh. 10.6 - Prob. 10CYUCh. 10.6 - Prob. 11CYUCh. 10.6 - Prob. 12CYUCh. 10.6 - Prob. 13CYUCh. 10.6 - Prob. 14CYUCh. 10.6 - Prob. 15PPSCh. 10.6 - Prob. 16PPSCh. 10.6 - Prob. 17PPSCh. 10.6 - Prob. 18PPSCh. 10.6 - Prob. 19PPSCh. 10.6 - Prob. 20PPSCh. 10.6 - Prob. 21PPSCh. 10.6 - Prob. 22PPSCh. 10.6 - Prob. 23PPSCh. 10.6 - Prob. 24PPSCh. 10.6 - Prob. 25PPSCh. 10.6 - Prob. 26PPSCh. 10.6 - Prob. 27PPSCh. 10.6 - Prob. 28PPSCh. 10.6 - Prob. 29PPSCh. 10.6 - Prob. 30PPSCh. 10.6 - Prob. 31PPSCh. 10.6 - Prob. 32PPSCh. 10.6 - Prob. 33PPSCh. 10.6 - Prob. 34PPSCh. 10.6 - Prob. 35PPSCh. 10.6 - Prob. 36PPSCh. 10.6 - Prob. 37PPSCh. 10.6 - Prob. 38HPCh. 10.6 - Prob. 39HPCh. 10.6 - Prob. 40HPCh. 10.6 - Prob. 41PFACh. 10.6 - Prob. 42PFACh. 10.6 - Prob. 43PFACh. 10 - Prob. 1MCQCh. 10 - Prob. 2MCQCh. 10 - Prob. 3MCQCh. 10 - Prob. 4MCQCh. 10 - Prob. 5MCQCh. 10 - Prob. 6MCQCh. 10 - Prob. 7MCQCh. 10 - Prob. 8MCQCh. 10 - Prob. 9MCQCh. 10 - Prob. 10MCQCh. 10 - Prob. 11MCQCh. 10 - Prob. 1SGRCh. 10 - Prob. 2SGRCh. 10 - Prob. 3SGRCh. 10 - Prob. 4SGRCh. 10 - Prob. 5SGRCh. 10 - Prob. 6SGRCh. 10 - Prob. 7SGRCh. 10 - Prob. 8SGRCh. 10 - Prob. 9SGRCh. 10 - Prob. 10SGRCh. 10 - Prob. 11SGRCh. 10 - Prob. 12SGRCh. 10 - Prob. 13SGRCh. 10 - Prob. 14SGRCh. 10 - Prob. 15SGRCh. 10 - Prob. 16SGRCh. 10 - Prob. 17SGRCh. 10 - Prob. 18SGRCh. 10 - Prob. 19SGRCh. 10 - Prob. 20SGRCh. 10 - Prob. 21SGRCh. 10 - Prob. 22SGRCh. 10 - Prob. 23SGRCh. 10 - Prob. 24SGRCh. 10 - Prob. 25SGRCh. 10 - Prob. 26SGRCh. 10 - Prob. 27SGRCh. 10 - Prob. 1PTCh. 10 - Prob. 2PTCh. 10 - Prob. 3PTCh. 10 - Prob. 4PTCh. 10 - Prob. 5PTCh. 10 - Prob. 6PTCh. 10 - Prob. 7PTCh. 10 - Prob. 8PTCh. 10 - Prob. 9PTCh. 10 - Prob. 10PTCh. 10 - Prob. 11PTCh. 10 - Prob. 12PTCh. 10 - Prob. 13PTCh. 10 - Prob. 1PFACh. 10 - Prob. 2PFACh. 10 - Prob. 3PFACh. 10 - Prob. 4PFACh. 10 - Prob. 5PFACh. 10 - Prob. 6PFACh. 10 - Prob. 7PFACh. 10 - Prob. 8PFACh. 10 - Prob. 9PFACh. 10 - Prob. 10PFACh. 10 - Prob. 11PFACh. 10 - Prob. 12PFACh. 10 - Prob. 13PFA
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