Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 10.5, Problem 19E

To determine

To find the surface area.

Expert Solution & Answer

Answer to Problem 19E

8201in²

Explanation of Solution

Given Information: 1 half cylinder with Radius = 4 in, Height = 180 in and π = 227 .

1 cuboid with Length = 8 in, Breadth = 180 in and Height = 8 in.

Formula Used:

Surface Area of Half-Cylinder = 12×2π×radius (height+ radius) ,

Surface Area of Cuboid = 2×(Length×Base + Base×Height + Height×Length)

Total Surface Area = Surface Area of Half-Cylinder + Surface Area of Cuboid

Calculation:

1 half cylinder with Radius = 4 in, Height = 180 in and π = 227 .

1 cuboid with Length = 8 in, Breadth = 180 in and Height = 8 in.

Total Surface Area = Surface Area of Half-Cylinder + Surface Area of Cuboid

Total Surface Area = 12×2π×radius (height+ radius) + 2×(Length×Base + Base×Height + Height×Length)

So,

Total Surface Area = π×radius (height+ radius) + 2×(Length×Base + Base×Height + Height×Length)

Put the value of Radius, Height, Length, breadth and π = 227 to find Surface Area

So,

Total Surface Area = 227×4 (180+ 4) + 2 ×(8×180 + 180×8 + 8×8) in² So,

Total Surface Area = 227×4 ×184 + 2 ×(1440 + 1440 + 64) in² So,

Total Surface Area = 227×736 + 2 ×2944 in² Hence,

Total Surface Area = 2313.14 + 5888 in² Hence,

Total Surface Area = 8201in²

Chapter 10.5, Problem 17E

Chapter 10.5, Problem 20E

Chapter 10 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 10.1 - Prob. 1C Ch. 10.1 - Prob. 2C Ch. 10.1 - Prob. 3C Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E

Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E Ch. 10.1 - Prob. 11E Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E Ch. 10.1 - Prob. 15E Ch. 10.1 - Prob. 16E Ch. 10.1 - Prob. 17E Ch. 10.1 - Prob. 18E Ch. 10.1 - Prob. 19E Ch. 10.1 - Prob. 20E Ch. 10.1 - Prob. 21E Ch. 10.1 - Prob. 22E Ch. 10.1 - Prob. 23E Ch. 10.1 - Prob. 24E Ch. 10.1 - Prob. 25E Ch. 10.1 - Prob. 26E Ch. 10.1 - Prob. 27E Ch. 10.1 - Prob. 28E Ch. 10.1 - Prob. 29E Ch. 10.1 - Prob. 30E Ch. 10.1 - Prob. 31E Ch. 10.1 - Prob. 32E Ch. 10.2 - Prob. 1C Ch. 10.2 - Prob. 2C Ch. 10.2 - Prob. 3C Ch. 10.2 - Prob. 1E Ch. 10.2 - Prob. 2E Ch. 10.2 - Prob. 3E Ch. 10.2 - Prob. 4E Ch. 10.2 - Prob. 5E Ch. 10.2 - Prob. 6E Ch. 10.2 - Prob. 7E Ch. 10.2 - Prob. 8E Ch. 10.2 - Prob. 9E Ch. 10.2 - Prob. 10E Ch. 10.2 - Prob. 11E Ch. 10.2 - Prob. 12E Ch. 10.2 - Prob. 13E Ch. 10.2 - Prob. 14E Ch. 10.2 - Prob. 15E Ch. 10.2 - Prob. 16E Ch. 10.2 - Prob. 17E Ch. 10.2 - Prob. 18E Ch. 10.2 - Prob. 19E Ch. 10.2 - Prob. 20E Ch. 10.2 - 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